1
AIEEE 2003
MCQ (Single Correct Answer)
+4
-1
The internal energy change when a system goes from state A to B is 40 kJ/mole. If the system goes from A to B by a reversible path and returns to state A by an irreversible path what would be the net change in internal energy?
A
> 40 kJ
B
< 40 kJ
C
Zero
D
40 kJ
2
AIEEE 2003
MCQ (Single Correct Answer)
+4
-1
If at 298 K the bond energies of C - H, C - C, C = C and H - H bonds are respectively 414, 347, 615 and 435 kJ/mol, the value of enthalpy change for the reaction
H2C = CH2(g) + H2(g) $$\to$$ H3C - CH3(g) at 298 K will be :
A
- 250 kJ
B
+ 125 kJ
C
- 125 kJ
D
+ 250 kJ
3
AIEEE 2003
MCQ (Single Correct Answer)
+4
-1
In an irreversible process taking place at constant T and P and in which only pressure-volume work is being done, the change in Gibbs free energy (dG) and change in entropy (dS), satisfy the criteria :
A
(dS)V, E > 0, (dG)T, P < 0
B
(dS)V, E = 0, (dG)T, P = 0
C
(dS)V, E = 0, (dG)T, P > 0
D
(dS)V, E < 0, (dG)T, P < 0
4
AIEEE 2003
MCQ (Single Correct Answer)
+4
-1
The correct relationship between free energy change in a reaction and the corresponding equilibrium constant Kc is :
A
- $$\Delta G$$ = RT ln Kc
B
$$\Delta G^o$$ = RT ln Kc
C
- $$\Delta G^o$$ = RT ln Kc
D
$$\Delta G$$ = RT ln Kc
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