JEE Main 2020 (Online) 9th January Morning Slot | Coordination Compounds Question 188 | Chemistry

Complex X of composition Cr(H₂O)₆Cl_n has a spin only magnetic moment of 3.83 BM. It reacts with AgNO₃ and shows geometrical isomerism. The IUPAC nomenclature of X is :

Hexaaqua chromium (III) chloride

Tetraaquadichlorido chromium(IV) chloride dihydrate

Tetraaquadichlorido chromium (III) chloride dihydrate

Dichloridotetraaqua chromium (IV) chloride dihydrate

JEE Main 2020 (Online) 9th January Morning Slot

MCQ (Single Correct Answer)

-1

[Pd(F)(Cl)(Br)(I)]^2– has n number of geometrical isomers. Then, the spin-only magnetic moment and crystal field stabilisation energy [CFSE] of [Fe(CN)₆]^n–6, respectively, are:
[Note : Ignore the pairing energy]

1.73 BM and –2.0 $$\Delta $$₀

5.92 BM and 0

2.84 BM and –1.6 $$\Delta $$₀

0 BM and –2.4 $$\Delta $$₀

JEE Main 2020 (Online) 8th January Evening Slot

MCQ (Single Correct Answer)

-1

Among (a) – (d) the complexes that can display geometrical isomerism are :
(a) [Pt(NH₃)₃Cl]⁺
(b) [Pt(NH₃)Cl₅]^–
(c) [Pt(NH₃)₂Cl(NO₂)]
(d) [Pt(NH₃)₄ClBr]²⁺

(a) and (b)

(d) and (a)

(b) and (c)

JEE Main 2020 (Online) 8th January Evening Slot

MCQ (Single Correct Answer)

-1

The correct order of the calculated spin-only magnetic moments of complexs (A) to (D) is:
(A) Ni(CO)₄
(B) [Ni(H₂O)₆]Cl₂
(C) Na₂[Ni(CN)₄]
(D) PdCl₂(PPh₃)₂

(A) $$ \approx $$ (C) $$ \approx $$ (D) < (B)

(A) $$ \approx $$ (C) < (B) $$ \approx $$ (D)

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