JEE Main 2022 (Online) 26th June Evening Shift | Statistics Question 72 | Mathematics

The mean and standard deviation of 50 observations are 15 and 2 respectively. It was found that one incorrect observation was taken such that the sum of correct and incorrect observations is 70. If the correct mean is 16, then the correct variance is equal to :

JEE Main 2022 (Online) 26th June Morning Shift

MCQ (Single Correct Answer)

-1

The mean of the numbers a, b, 8, 5, 10 is 6 and their variance is 6.8. If M is the mean deviation of the numbers about the mean, then 25 M is equal to :

JEE Main 2021 (Online) 31st August Evening Shift

MCQ (Single Correct Answer)

-1

The mean and variance of 7 observations are 8 and 16 respectively. If two observations are 6 and 8, then the variance of the remaining 5 observations is :

$${{92} \over 5}$$

$${{134} \over 5}$$

$${{536} \over {25}}$$

$${{112} \over 5}$$

JEE Main 2021 (Online) 26th August Morning Shift

MCQ (Single Correct Answer)

-1

The mean and standard deviation of 20 observations were calculated as 10 and 2.5 respectively. It was found that by mistake one data value was taken as 25 instead of 35. if $$\alpha$$ and $$\sqrt \beta $$ are the mean and standard deviation respectively for correct data, then ($$\alpha$$, $$\beta$$) is :

(11, 26)

(10.5, 25)

(11, 25)

(10.5, 26)

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