JEE Main 2024 (Online) 31st January Evening Shift | Statistics Question 10 | Mathematics

If the mean and variance of five observations are $$\frac{24}{5}$$ and $$\frac{194}{25}$$ respectively and the mean of the first four observations is $$\frac{7}{2}$$, then the variance of the first four observations in equal to

$$\frac{5}{4}$$

$$\frac{4}{5}$$

$$\frac{105}{4}$$

$$\frac{77}{12}$$

JEE Main 2024 (Online) 27th January Morning Shift

MCQ (Single Correct Answer)

-1

Let $\mathrm{a}_1, \mathrm{a}_2, \ldots \mathrm{a}_{10}$ be 10 observations such that $\sum\limits_{\mathrm{k}=1}^{10} \mathrm{a}_{\mathrm{k}}=50$ and $\sum\limits_{\forall \mathrm{k} < \mathrm{j}} \mathrm{a}_{\mathrm{k}} \cdot \mathrm{a}_{\mathrm{j}}=1100$. Then the standard deviation of $\mathrm{a}_1, \mathrm{a}_2, \ldots, \mathrm{a}_{10}$ is equal to :

$\sqrt{115}$

$\sqrt{5}$

PREVIOUS NEXT

Questions Asked from Statistics (MCQ (Single Correct Answer))

Number in Brackets after Paper Indicates No. of Questions