1
JEE Main 2019 (Online) 9th April Morning Slot
+4
-1
If the standard deviation of the numbers –1, 0, 1, k is $$\sqrt 5$$ where k > 0, then k is equal to
A
2$$\sqrt 6$$
B
$$\sqrt 6$$
C
$$2\sqrt {{{5} \over 6}}$$
D
$$2\sqrt {{{10} \over 3}}$$
2
JEE Main 2019 (Online) 8th April Evening Slot
+4
-1
A student scores the following marks in five tests :

45, 54, 41, 57, 43.

His score is not known for the sixth test. If the mean score is 48 in the six tests, then the standard deviation of the marks in six tests is
A
$$100 \over {\sqrt 3}$$
B
$$10 \over {\sqrt 3}$$
C
$$10 \over3$$
D
$$100 \over3$$
3
JEE Main 2019 (Online) 8th April Morning Slot
+4
-1
The mean and variance of seven observations are 8 and 16, respectively. If 5 of the observations are 2, 4, 10, 12, 14, then the product of the remaining two observations is :
A
40
B
48
C
49
D
45
4
JEE Main 2019 (Online) 12th January Evening Slot
+4
-1
The mean and the variance of five observations are 4 and 5.20, respectively. If three of the observations are 3, 4 and 4 ; then the absolute value of the difference of the other two observations, is :
A
1
B
7
C
3
D
5
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