JEE Main 2025 (Online) 23rd January Morning Shift | Statistics Question 4 | Mathematics

Marks obtains by all the students of class 12 are presented in a freqency distribution with classes of equal width. Let the median of this grouped data be 14 with median class interval 12-18 and median class frequency 12. If the number of students whose marks are less than 12 is 18 , then the total number of students is :

JEE Main 2024 (Online) 9th April Evening Shift

MCQ (Single Correct Answer)

-1

If the variance of the frequency distribution

$$x$$	$$c$$	$$2c$$	$$3c$$	$$4c$$	$$5c$$	$$6c$$
$$f$$	2	1	1	1	1	1

is 160, then the value of $$c\in N$$ is

JEE Main 2024 (Online) 9th April Morning Shift

MCQ (Single Correct Answer)

-1

The frequency distribution of the age of students in a class of 40 students is given below.

Age	15	16	17	18	19	20
No of Students	5	8	5	12	$$x$$	$$y$$

If the mean deviation about the median is 1.25, then $$4x+5y$$ is equal to :

JEE Main 2024 (Online) 6th April Morning Shift

MCQ (Single Correct Answer)

-1

The mean and standard deviation of 20 observations are found to be 10 and 2 , respectively. On rechecking, it was found that an observation by mistake was taken 8 instead of 12. The correct standard deviation is

1.94

$$\sqrt{3.96}$$

$$\sqrt{3.86}$$

1.8

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