1
JEE Main 2023 (Online) 11th April Evening Shift
+4
-1

Let the mean of 6 observations $$1,2,4,5, \mathrm{x}$$ and $$\mathrm{y}$$ be 5 and their variance be 10 . Then their mean deviation about the mean is equal to :

A
$$\frac{10}{3}$$
B
$$\frac{8}{3}$$
C
$$\frac{7}{3}$$
D
3
2
JEE Main 2023 (Online) 11th April Morning Shift
+4
-1

Let sets A and B have 5 elements each. Let the mean of the elements in sets A and B be 5 and 8 respectively and the variance of the elements in sets A and B be 12 and 20 respectively. A new set C of 10 elements is formed by subtracting 3 from each element of $$\mathrm{A}$$ and adding 2 to each element of $$\mathrm{B}$$. Then the sum of the mean and variance of the elements of $$\mathrm{C}$$ is ___________.

A
36
B
40
C
38
D
32
3
JEE Main 2023 (Online) 10th April Evening Shift
+4
-1

Let $$\mu$$ be the mean and $$\sigma$$ be the standard deviation of the distribution

$${x_i}$$ 0 1 2 3 4 5
$${f_i}$$ $$k + 2$$ $$2k$$ $${k^2} - 1$$ $${k^2} - 1$$ $${k^2} + 1$$ $$k - 3$$

where $$\sum f_{i}=62$$. If $$[x]$$ denotes the greatest integer $$\leq x$$, then $$\left[\mu^{2}+\sigma^{2}\right]$$ is equal to :

A
9
B
8
C
6
D
7
4
JEE Main 2023 (Online) 8th April Evening Shift
+4
-1

Let the mean and variance of 12 observations be $$\frac{9}{2}$$ and 4 respectively. Later on, it was observed that two observations were considered as 9 and 10 instead of 7 and 14 respectively. If the correct variance is $$\frac{m}{n}$$, where $$\mathrm{m}$$ and $$\mathrm{n}$$ are coprime, then $$\mathrm{m}+\mathrm{n}$$ is equal to :

A
317
B
316
C
314
D
315
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