Given below are two statements:
Statement I: $$\mathrm{N}\left(\mathrm{CH}_3\right)_3$$ and $$\mathrm{P}\left(\mathrm{CH}_3\right)_3$$ can act as ligands to form transition metal complexes.
Statement II: As N and P are from same group, the nature of bonding of $$\mathrm{N}\left(\mathrm{CH}_3\right)_3$$ and $$\mathrm{P}\left(\mathrm{CH}_3\right)_3$$ is always same with transition metals.
In the light of the above statements, choose the most appropriate answer from the options given below:
Match List I with List II
LIST I (Compound) |
LIST II (Colour] |
||
---|---|---|---|
A. | $$\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3 \cdot \mathrm{xH_2O}$$ | I. | Violet |
B. | $$\left[\mathrm{Fe}(\mathrm{CN})_5 \mathrm{NOS}\right]^{4-}$$ | II. | Blood Red |
C. | $$[\mathrm{Fe}(\mathrm{SCN})]^{2+}$$ | III. | Prussian Blue |
D. | $$\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4\cdot12 \mathrm{MoO}_3$$ | IV. | Yellow |
Choose the correct answer from the options given below:
Given below are two statements :
Statement I: $$\mathrm{PF}_5$$ and $$\mathrm{BrF}_5$$ both exhibit $$\mathrm{sp}^3 \mathrm{~d}$$ hybridisation.
Statement II: Both $$\mathrm{SF}_6$$ and $$[\mathrm{Co}(\mathrm{NH}_3)_6]^{3+}$$ exhibit $$\mathrm{sp}^3 \mathrm{~d}^2$$ hybridisation.
In the light of the above statements, choose the correct answer from the options given below :
Match List I with List II.
LIST I Tetrahedral Complex |
LIST II Electronic configuration |
||
---|---|---|---|
A. | $$ \mathrm{TiCl}_4 $$ |
I. | $$ \mathrm{e}^2, \mathrm{t}_2^0 $$ |
B. | $$ \left[\mathrm{FeO}_4\right]^{2-} $$ |
II. | $$ \mathrm{e^4, t_2^3} $$ |
C. | $$ \left[\mathrm{FeCl}_4\right]^{-} $$ |
III. | $$ \mathrm{e}^0, \mathrm{t}_2^0 $$ |
D. | $$ \left[\mathrm{CoCl}_4\right]^{2-} $$ |
IV. | $$ \mathrm{e}^2, \mathrm{t}_2^3 $$ |
Choose the correct answer from the options given below :