1
JEE Main 2025 (Online) 4th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Match List - I with List - II.

List - I List - II
(A) Isobaric (I) $\Delta Q=\Delta W$
(B) Isochoric (II) $\Delta Q=\Delta U$
(C) Adiabatic (III) $\Delta Q=$ zero
(D) Isothermal (IV) $\Delta Q=\Delta U+P\Delta V$

$\Delta Q=$ Heat supplied

$\Delta W=$ Work done by the system

$\Delta \mathrm{U}=$ Change in internal energy

$\mathrm{P}=$ Pressure of the system

$\Delta \mathrm{V}=$ Change in volume of the system

Choose the correct answer from the options given below :

A
(A)-(IV), (B)-(I), (C)-(III), (D)-(II)
B
(A)-(IV), (B)-(II), (C)-(III), (D)-(I)
C
(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
D
(A)-(II), (B)-(IV), (C)-(III), (D)-(I)
2
JEE Main 2025 (Online) 4th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

There are ' $n$ ' number of identical electric bulbs, each is designed to draw a power $p$ independently from the mains supply. They are now joined in series across the mains supply. The total power drawn by the combination is :

A
np
B
p
C
$\frac{\mathrm{p}}{\mathrm{n}^2}$
D
$\frac{p}{n}$
3
JEE Main 2025 (Online) 4th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

From the combination of resistors with resistances values $R_1=R_2=R_3=5 \Omega$ and $R_4=10 \Omega$, which of the following combination is the best circuit to get an equivalent resistance of $6 \Omega$ ?

A
JEE Main 2025 (Online) 4th April Evening Shift Physics - Current Electricity Question 4 English Option 1
B
JEE Main 2025 (Online) 4th April Evening Shift Physics - Current Electricity Question 4 English Option 2
C
JEE Main 2025 (Online) 4th April Evening Shift Physics - Current Electricity Question 4 English Option 3
D
JEE Main 2025 (Online) 4th April Evening Shift Physics - Current Electricity Question 4 English Option 4
4
JEE Main 2025 (Online) 4th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Consider a n-type semiconductor in which $\mathrm{n}_{\mathrm{e}}$ and $\mathrm{n}_{\mathrm{h}}$ are number of electrons and holes, respectively.

(A) Holes are minority carriers

(B) The dopant is a pentavalent atom

(C) $\mathrm{n}_{\mathrm{e}} \mathrm{n}_{\mathrm{h}} \neq \mathrm{n}_i^2$

(where $\mathrm{n}_i$ is number of electrons or holes in semiconductor when it is intrinsic form)

(D) $\mathrm{n}_{\mathrm{e}} \mathrm{n}_{\mathrm{h}} \geqslant \mathrm{n}_i^2$

(E) The holes are not generated due to the donors

Choose the correct answer from the options given below :

A
(A), (B), (E) only
B
(A), (C), (E) only
C
(A), (B), (C) only
D
(A), (C), (D) only
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