1
JEE Main 2025 (Online) 4th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

There are two vessels filled with an ideal gas where volume of one is double the volume of other. The large vessel contains the gas at 8 kPa at 1000 K while the smaller vessel contains the gas at 7 kPa at 500 K . If the vessels are connected to each other by a thin tube allowing the gas to flow and the temperature of both vessels is maintained at 600 K , at steady state the pressure in the vessels will be (in kPa ).

A
24
B
4.4
C
18
D
6
2
JEE Main 2025 (Online) 4th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Two polarisers $P_1$ and $P_2$ are placed in such a way that the intensity of the transmitted light will be zero. A third polariser $P_3$ is inserted in between $P_1$ and $P_2$, at particular angle between $P_2$ and $P_3$. The transmitted intensity of the light passing the through all three polarisers is maximum. The angle between the polarisers $P_2$ and $P_3$ is :

A
$\pi / 6$
B
$\frac{\pi}{3}$
C
$\frac{\pi}{4}$
D
$\pi / 8$
3
JEE Main 2025 (Online) 4th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Match List - I with List - II.

List - I List - II
(A) Isobaric (I) $\Delta Q=\Delta W$
(B) Isochoric (II) $\Delta Q=\Delta U$
(C) Adiabatic (III) $\Delta Q=$ zero
(D) Isothermal (IV) $\Delta Q=\Delta U+P\Delta V$

$\Delta Q=$ Heat supplied

$\Delta W=$ Work done by the system

$\Delta \mathrm{U}=$ Change in internal energy

$\mathrm{P}=$ Pressure of the system

$\Delta \mathrm{V}=$ Change in volume of the system

Choose the correct answer from the options given below :

A
(A)-(IV), (B)-(I), (C)-(III), (D)-(II)
B
(A)-(IV), (B)-(II), (C)-(III), (D)-(I)
C
(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
D
(A)-(II), (B)-(IV), (C)-(III), (D)-(I)
4
JEE Main 2025 (Online) 4th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

There are ' $n$ ' number of identical electric bulbs, each is designed to draw a power $p$ independently from the mains supply. They are now joined in series across the mains supply. The total power drawn by the combination is :

A
np
B
p
C
$\frac{\mathrm{p}}{\mathrm{n}^2}$
D
$\frac{p}{n}$
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