1
JEE Main 2019 (Online) 9th April Evening Slot
+4
-1
The common tangent to the circles x 2 + y2 = 4 and x2 + y2 + 6x + 8y – 24 = 0 also passes through the point :-
A
(6, –2)
B
(4, –2)
C
(–4, 6)
D
(–6, 4)
2
JEE Main 2019 (Online) 9th April Evening Slot
+4
-1
A rectangle is inscribed in a circle with a diameter lying along the line 3y = x + 7. If the two adjacent vertices of the rectangle are (–8, 5) and (6, 5), then the area of the rectangle (in sq. units) is :-
A
72
B
84
C
56
D
98
3
JEE Main 2019 (Online) 9th April Morning Slot
+4
-1
If a tangent to the circle x2 + y2 = 1 intersects the coordinate axes at distinct points P and Q, then the locus of the mid-point of PQ is
A
x2 + y2 – 4x2y2 = 0
B
x2 + y2 - 2xy = 0
C
x2 + y2 – 2x2y2 = 0
D
x2 + y2 - 16x2y2 = 0
4
JEE Main 2019 (Online) 8th April Evening Slot
+4
-1
The tangent and the normal lines at the point ( $$\sqrt 3$$, 1) to the circle x2 + y2 = 4 and the x-axis form a triangle. The area of this triangle (in square units) is :
A
$${4 \over {\sqrt 3 }}$$
B
$${1 \over {\sqrt 3 }}$$
C
$${2 \over {\sqrt 3 }}$$
D
$${1 \over {3 }}$$
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