JEE Main 2022 (Online) 25th June Morning Shift | Circle Question 32 | Mathematics

JEE Main 2022 (Online) 25th June Morning Shift

MCQ (Single Correct Answer)

-1

Let a circle C touch the lines $${L_1}:4x - 3y + {K_1} = 0$$ and $${L_2} = 4x - 3y + {K_2} = 0$$, $${K_1},{K_2} \in R$$. If a line passing through the centre of the circle C intersects L₁ at $$( - 1,2)$$ and L₂ at $$(3, - 6)$$, then the equation of the circle C is :

$${(x - 1)^2} + {(y - 2)^2} = 4$$

$${(x + 1)^2} + {(y - 2)^2} = 4$$

$${(x - 1)^2} + {(y + 2)^2} = 16$$

$${(x - 1)^2} + {(y - 2)^2} = 16$$

JEE Main 2022 (Online) 25th June Morning Shift

MCQ (Single Correct Answer)

-1

Let a, b and c be the length of sides of a triangle ABC such that $${{a + b} \over 7} = {{b + c} \over 8} = {{c + a} \over 9}$$. If r and R are the radius of incircle and radius of circumcircle of the triangle ABC, respectively, then the value of $${R \over r}$$ is equal to :

$${5 \over 2}$$

$${3 \over 2}$$

JEE Main 2021 (Online) 27th August Evening Shift

MCQ (Single Correct Answer)

-1

Let Z be the set of all integers,

$$A = \{ (x,y) \in Z \times Z:{(x - 2)^2} + {y^2} \le 4\} $$

$$B = \{ (x,y) \in Z \times Z:{x^2} + {y^2} \le 4\} $$

$$C = \{ (x,y) \in Z \times Z:{(x - 2)^2} + {(y - 2)^2} \le 4\} $$

If the total number of relation from A $$\cap$$ B to A $$\cap$$ C is 2^p, then the value of p is :

JEE Main 2021 (Online) 26th August Evening Shift

MCQ (Single Correct Answer)

-1

A circle C touches the line x = 2y at the point (2, 1) and intersects the circle

C₁ : x² + y² + 2y $$-$$ 5 = 0 at two points P and Q such that PQ is a diameter of C₁. Then the diameter of C is :

$$7\sqrt 5 $$

$$\sqrt {285} $$

$$4\sqrt {15} $$

PREVIOUS NEXT