JEE Main 2021 (Online) 26th February Morning Shift | Circle Question 60 | Mathematics

JEE Main 2021 (Online) 26th February Morning Shift

MCQ (Single Correct Answer)

-1

In the circle given below, let OA = 1 unit, OB = 13 unit and PQ $$ \bot $$ OB. Then, the area of the triangle PQB (in square units) is :

JEE Main 2021 (Online) 26th February Morning Shift Mathematics - Circle Question 60 English

JEE Main 2021 (Online) 26th February Morning Shift Mathematics - Circle Question 60 English

24$$\sqrt 2 $$

24$$\sqrt 3 $$

26$$\sqrt 2 $$

26$$\sqrt 3 $$

JEE Main 2021 (Online) 25th February Evening Shift

MCQ (Single Correct Answer)

-1

If the curve x² + 2y² = 2 intersects the line x + y = 1 at two points P and Q, then the angle subtended by the line segment PQ at the origin is :

$${\pi \over 2} - {\tan ^{ - 1}}\left( {{1 \over 4}} \right)$$

$${\pi \over 2} + {\tan ^{ - 1}}\left( {{1 \over 3}} \right)$$

$${\pi \over 2} - {\tan ^{ - 1}}\left( {{1 \over 3}} \right)$$

$${\pi \over 2} + {\tan ^{ - 1}}\left( {{1 \over 4}} \right)$$

JEE Main 2021 (Online) 24th February Evening Shift

MCQ (Single Correct Answer)

-1

Let a, b, c be in arithmetic progression. Let the centroid of the triangle with vertices (a, c), (2, b) and (a, b) be $$\left( {{{10} \over 3},{7 \over 3}} \right)$$. If $$\alpha$$, $$\beta$$ are the roots of the equation $$a{x^2} + bx + 1 = 0$$, then the value of $${\alpha ^2} + {\beta ^2} - \alpha \beta $$ is :

$${{69} \over {256}}$$

$${{71} \over {256}}$$

$$ - {{71} \over {256}}$$

$$ - {{69} \over {256}}$$

JEE Main 2020 (Online) 5th September Evening Slot

MCQ (Single Correct Answer)

-1

If the length of the chord of the circle,
x² + y² = r² (r > 0) along the line, y – 2x = 3 is r,
then r² is equal to :

$${9 \over 5}$$

$${{24} \over 5}$$

$${{12} \over 5}$$

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