The area (in sq. units) in the first quadrant bounded by the parabola, y = x² + 1, the tangent to it at the point (2, 5) and the coordinate axes is :

The area (in sq. units) of the region bounded by the curve x² = 4y and the straight line x = 4y – 2 is :

If the area enclosed between the curves y = kx² and x = ky², (k > 0), is 1 square unit. Then k is -

The area of the region

A = {(x, y) : 0 $$ \le $$ y $$ \le $$x |x| + 1  and  $$-$$1 $$ \le $$ x $$ \le $$1} in sq. units, is :