1
JEE Main 2025 (Online) 24th January Evening Shift
MCQ (Single Correct Answer)
+4
-1

JEE Main 2025 (Online) 24th January Evening Shift Physics - Electrostatics Question 3 English

In the first configuration (1) as shown in the figure, four identical charges $\left(q_0\right)$ are kept at the corners A, B, C and D of square of side length ' $a$ '. In the second configuration (2), the same charges are shifted to mid points $G, E, H$ and $F$, of the square. If $K=\frac{1}{4 \pi \epsilon_0}$, the difference between the potential energies of configuration (2) and (1) is given by :

A
$\frac{K q_0^2}{a}(4-2 \sqrt{2})$
B
$\frac{K q_0^2}{a}(4 \sqrt{2}-2)$
C
$\frac{\mathrm{Kq}_0^2}{\mathrm{a}}(3-\sqrt{2})$
D
$\frac{\mathrm{Kq}_0^2}{\mathrm{a}}(3 \sqrt{2}-2)$
2
JEE Main 2025 (Online) 24th January Evening Shift
MCQ (Single Correct Answer)
+4
-1

A particle oscillates along the $x$-axis according to the law, $x(\mathrm{t})=x_0 \sin ^2\left(\frac{\mathrm{t}}{2}\right)$ where $x_0=1 \mathrm{~m}$. The kinetic energy $(\mathrm{K})$ of the particle as a function of $x$ is correctly represented by the graph

A
JEE Main 2025 (Online) 24th January Evening Shift Physics - Simple Harmonic Motion Question 1 English Option 1
B
JEE Main 2025 (Online) 24th January Evening Shift Physics - Simple Harmonic Motion Question 1 English Option 2
C
JEE Main 2025 (Online) 24th January Evening Shift Physics - Simple Harmonic Motion Question 1 English Option 3
D
JEE Main 2025 (Online) 24th January Evening Shift Physics - Simple Harmonic Motion Question 1 English Option 4
3
JEE Main 2025 (Online) 24th January Evening Shift
Numerical
+4
-1

The ratio of the power of a light source $S_1$ to that the light source $S_2$ is $2 . S_1$ is emitting $2 \times 10^{15}$ photons per second at 600 nm . If the wavelength of the source $S_2$ is 300 nm , then the number of photons per second emitted by $S_2$ is __________ $\times 10^{14}$.

Your input ____
4
JEE Main 2025 (Online) 24th January Evening Shift
Numerical
+4
-1

The increase in pressure required to decrease the volume of a water sample by $0.2 \%$ is $\mathrm{P} \times 10^5 \mathrm{Nm}^{-2}$. Bulk modulus of water is $2.15 \times 10^9 \mathrm{Nm}^{-2}$. The value of P is _________ .

Your input ____
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