1
JEE Main 2025 (Online) 24th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The output of the circuit is low (zero) for :

JEE Main 2025 (Online) 24th January Evening Shift Physics - Semiconductor Question 11 English

(A) $X=0, Y=0$

(B) $X=0, Y=1$

(C) $X=1, Y=0$

(D) $X=1, Y=1$

Choose the correct answer from the options given below :

A
(A), (B) and (C) only
B
(A), (C) and (D) only
C
(B), (C) and (D) only
D
(A), (B) and (D) only
2
JEE Main 2025 (Online) 24th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The magnitude of heat exchanged by a system for the given cyclic process ABCA (as shown in figure) is (in SI unit) :

JEE Main 2025 (Online) 24th January Evening Shift Physics - Heat and Thermodynamics Question 27 English

A
zero
B
40$\pi$
C
5$\pi$
D
10$\pi$
3
JEE Main 2025 (Online) 24th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

In photoelectric effect, the stopping potential $\left(\mathrm{V}_0\right) \mathrm{v} / \mathrm{s}$ frequency $(v)$ curve is plotted.

( h is the Planck's constant and $\phi_0$ is work function of metal )

(A) $\mathrm{V}_0 \mathrm{v} / \mathrm{s} v$ is linear.

(B) The slope of $\mathrm{V}_0 \mathrm{v} / \mathrm{s} v$ curve $=\frac{\phi_0}{\mathrm{~h}}$

(C) h constant is related to the slope of $\mathrm{V}_0 \mathrm{v} / \mathrm{s} v$ line.

(D) The value of electric charge of electron is not required to determine h using the $\mathrm{V}_0 \mathrm{v} / \mathrm{s} v$ curve.

(E) The work function can be estimated without knowing the value of $h$.

Choose the correct answer from the options given below :

A
(A), (C) and (E) only
B
(C) and (D) only
C
(A), (B) and (C) only
D
(D) and (E) only
4
JEE Main 2025 (Online) 24th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

A small uncharged conducting sphere is placed in contact with an identical sphere but having $4 \times 10^{-8} \mathrm{C}$ charge and then removed to a distance such that the force of repulsion between them is $9 \times 10^{-3} \mathrm{~N}$. The distance between them is (Take $\frac{1}{4 \pi \epsilon_{\mathrm{o}}}$ as $9 \times 10^9$ in SI units)

A
1 cm
B
2 cm
C
4 cm
D
3 cm
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