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1
JEE Main 2023 (Online) 1st February Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

In the following reaction, 'A' is

JEE Main 2023 (Online) 1st February Morning Shift Chemistry - Compounds Containing Nitrogen Question 106 English

A
JEE Main 2023 (Online) 1st February Morning Shift Chemistry - Compounds Containing Nitrogen Question 106 English Option 1
B
JEE Main 2023 (Online) 1st February Morning Shift Chemistry - Compounds Containing Nitrogen Question 106 English Option 2
C
JEE Main 2023 (Online) 1st February Morning Shift Chemistry - Compounds Containing Nitrogen Question 106 English Option 3
D
JEE Main 2023 (Online) 1st February Morning Shift Chemistry - Compounds Containing Nitrogen Question 106 English Option 4
2
JEE Main 2023 (Online) 1st February Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

A solution of $$\mathrm{FeCl_3}$$ when treated with $$\mathrm{K_4[Fe(CN)_6]}$$ gives a prussium blue precipitate due to the formation of :

A
$$\mathrm{Fe[Fe(CN)_{6}]}$$
B
$$\mathrm{Fe_{4}[Fe(CN)_{6}]_{3}}$$
C
$$\mathrm{Fe_{3}[Fe(CN)_{6}]_{2}}$$
D
$$\mathrm{K[Fe_{2}(CN)_{6}]}$$
3
JEE Main 2023 (Online) 1st February Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Identify the incorrect option from the following

A
JEE Main 2023 (Online) 1st February Morning Shift Chemistry - Alcohols, Phenols and Ethers Question 72 English Option 1
B
JEE Main 2023 (Online) 1st February Morning Shift Chemistry - Alcohols, Phenols and Ethers Question 72 English Option 2
C
JEE Main 2023 (Online) 1st February Morning Shift Chemistry - Alcohols, Phenols and Ethers Question 72 English Option 3
D
JEE Main 2023 (Online) 1st February Morning Shift Chemistry - Alcohols, Phenols and Ethers Question 72 English Option 4
4
JEE Main 2023 (Online) 1st February Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Decreasing order of dehydration of the following alcohols is

JEE Main 2023 (Online) 1st February Morning Shift Chemistry - Alcohols, Phenols and Ethers Question 73 English

A
d > b > c > a
B
b > d > c > a
C
a > d > b > c
D
b > a > d > c

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