1
JEE Main 2023 (Online) 1st February Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Resonance in carbonate ion $$\left(\mathrm{CO}_{3}{ }^{2-}\right)$$ is

JEE Main 2023 (Online) 1st February Morning Shift Chemistry - Basics of Organic Chemistry Question 82 English

Which of the following is true?

A
It is possible to identify each structure individually by some physical or chemical method.
B
All these structures are in dynamic equilibrium with each other.
C
Each structure exists for equal amount of time.
D
$$\mathrm{CO}_{3}{ }^{2-}$$ has a single structure i.e., resonance hybrid of the above three structures.
2
JEE Main 2023 (Online) 1st February Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Match List I with List II

List I List II
Test Functional group / Class of Compound
A. Molisch's Test I. Peptide
B. Biuret Test II. Carbohydrate
C. Carbylamine Test III. Primary amine
D. Schiff's Test IV. Aldehyde

Choose the correct answer from the options given below :

A
(A) - III, (B) - IV, (C) - II, (D) - I
B
(A) - II, (B) - I, (C) - III, (D) - IV
C
(A) - III, (B) - IV, (C) - I, (D) - II
D
(A) - I, (B) - II, (C) - III, (D) - IV
3
JEE Main 2023 (Online) 1st February Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

In the following reaction, 'A' is

JEE Main 2023 (Online) 1st February Morning Shift Chemistry - Compounds Containing Nitrogen Question 59 English

A
JEE Main 2023 (Online) 1st February Morning Shift Chemistry - Compounds Containing Nitrogen Question 59 English Option 1
B
JEE Main 2023 (Online) 1st February Morning Shift Chemistry - Compounds Containing Nitrogen Question 59 English Option 2
C
JEE Main 2023 (Online) 1st February Morning Shift Chemistry - Compounds Containing Nitrogen Question 59 English Option 3
D
JEE Main 2023 (Online) 1st February Morning Shift Chemistry - Compounds Containing Nitrogen Question 59 English Option 4
4
JEE Main 2023 (Online) 1st February Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

A solution of $$\mathrm{FeCl_3}$$ when treated with $$\mathrm{K_4[Fe(CN)_6]}$$ gives a prussium blue precipitate due to the formation of :

A
$$\mathrm{Fe[Fe(CN)_{6}]}$$
B
$$\mathrm{Fe_{4}[Fe(CN)_{6}]_{3}}$$
C
$$\mathrm{Fe_{3}[Fe(CN)_{6}]_{2}}$$
D
$$\mathrm{K[Fe_{2}(CN)_{6}]}$$
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