1
JEE Main 2018 (Online) 15th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The total number of possible isomers for square-planar [Pt(Cl)(NO2)(NO3)(SCN)]2- is :
A
8
B
12
C
16
D
24
2
JEE Main 2018 (Online) 15th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Two compounds I and II are eluted by column chromatography (adsorption of I > II). Which one of following is a correct statement ?
A
I moves faster and has higher Rf value than II
B
II movesfaster and has higher  Rf  value than I
C
I moves slower and has higher  Rf  value than II
D
II moves slower and has higher  Rf  value than I
3
JEE Main 2018 (Online) 15th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The correct order of spin-only magnetic moments among the following is :
(Atomic number : Mn = 25, Co = 27, Ni = 28, Zn = 30)
A
[ZnCl4]2- > [NiCl4]2- > [CoCl4]2- > [MnCl4]2-
B
[CoCl4]2- > [MnCl4]2- > [NiCl4]2- > [ZnCl4]2-
C
[NiCl4]2- > [CoCl4]2- > [MnCl4]2- > [ZnCl4]2-
D
[MnCl4]2- > [CoCl4]2- > [NiCl4]2- > [ZnCl4]2-
4
JEE Main 2018 (Online) 15th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Given

(i)   2Fe2O3(s) $$ \to $$ 4Fe(s) + 3O2(g);

$$\Delta $$rGo = + 1487.0 kJ mol-1

(ii)   2CO(g) + O2(g) $$ \to $$ 2CO2(g);

$$\Delta $$rGo = $$-$$ 514.4 kJ mol-1

Free energy change, $$\Delta $$rGo for the reaction

2Fe2O3(s) + 6CO(g) $$ \to $$ 4Fe(s) + 6CO2(g) will be :
A
$$-$$ 112.4 kJ mol-1
B
$$-$$ 56.2 kJ mol-1
C
$$-$$ 168.2 kJ mol-1
D
$$-$$ 208.0 kJ mol-1
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