Given

(i)   2Fe₂O₃(s) $$ \to $$ 4Fe(s) + 3O₂(g);

$$\Delta $$_rG^o = + 1487.0 kJ mol^-1

(ii)   2CO(g) + O₂(g) $$ \to $$ 2CO₂(g);

$$\Delta $$_rG^o = $$-$$ 514.4 kJ mol^-1

Free energy change, $$\Delta $$_rG^o for the reaction

2Fe₂O₃(s) + 6CO(g) $$ \to $$ 4Fe(s) + 6CO₂(g) will be :

At a certain temperature in a $$5$$ $$L$$ vessel, 2 moles of carbon monoxide and 3 moles of chlorine were allowed to reach equilibrium according to the reaction,
         CO + Cl₂ $$\rightleftharpoons$$ COCl₂
At equilibrium, if one mole of CO is present then equilibrium constant (K_c) for the reaction is :

The correct order of electron affinity is :

Two 5 molal solutions are prepared by dissolving a non-electrolyte non-volatile solute separately in the solvents X and Y. The molecular weights of the solvents are M_x and M_y, respectively where M_x = $${3 \over 4}$$ My. The relative lowering of vapor pressure of the solution in X is ''m'' times that of the solution in Y. Given that the number of moles of solute is very small in comparison to that of the solvent, the value of ''m'' is :