1
JEE Main 2018 (Online) 15th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The correct order of electron affinity is :
A
F > Cl > O
B
F > O > Cl
C
Cl > F > O
D
O > F > Cl
2
JEE Main 2018 (Online) 15th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Two 5 molal solutions are prepared by dissolving a non-electrolyte non-volatile solute separately in the solvents X and Y. The molecular weights of the solvents are Mx and My, respectively where Mx = $${3 \over 4}$$ My. The relative lowering of vapor pressure of the solution in X is ''m'' times that of the solution in Y. Given that the number of moles of solute is very small in comparison to that of the solvent, the value of ''m'' is :
A
$${4 \over 3}$$
B
$${3 \over 4}$$
C
$${1 \over 2}$$
D
$${1 \over 4}$$
3
JEE Main 2018 (Online) 15th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
For a first order reaction, A $$ \to $$ P, t1/2 (half-life) is 10 days The time required for $${1 \over 4}$$th conversion of A (in days) is : (ln 2 = 0.693,    ln 3 = 1.1)
A
5
B
3.2
C
4.1
D
2.5
4
JEE Main 2018 (Online) 15th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
In KO2, the nature of oxygen species and the oxydation state of oxygen atom are, respectively :
A
Oxide and $$-$$ 2
B
Superoxide and $$-$$ 1/2
C
Peroxide and $$-$$ 1/2
D
Superoxide and $$-$$ 1
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