1
JEE Main 2018 (Online) 15th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Let f : A $$ \to $$ B be a function defined as f(x) = $${{x - 1} \over {x - 2}},$$ Where A = R $$-$$ {2} and B = R $$-$$ {1}. Then   f   is :
A
invertible and $${f^{ - 1}}(y) = $$ $${{3y - 1} \over {y - 1}}$$
B
invertible and $${f^{ - 1}}\left( y \right) = {{2y - 1} \over {y - 1}}$$
C
invertible and $${f^{ - 1}}\left( y \right) = {{2y + 1} \over {y - 1}}$$
D
not invertible
2
JEE Main 2018 (Online) 15th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
An angle between the lines whose direction cosines are gien by the equations,
$$l$$ + 3m + 5n = 0 and 5$$l$$m $$-$$ 2mn + 6n$$l$$ = 0, is :
A
$${\cos ^{ - 1}}\left( {{1 \over 3}} \right)$$
B
$${\cos ^{ - 1}}\left( {{1 \over 4}} \right)$$
C
$${\cos ^{ - 1}}\left( {{1 \over 6}} \right)$$
D
$${\cos ^{ - 1}}\left( {{1 \over 8}} \right)$$
3
JEE Main 2018 (Online) 15th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The curve satifying the differeial equation, (x2 $$-$$ y2) dx + 2xydy = 0 and passing through the point (1, 1) is :
A
a circle of radius one.
B
a hyperbola.
C
an ellipse.
D
a circle of radius two.
4
JEE Main 2018 (Online) 15th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If    $$\int {{{2x + 5} \over {\sqrt {7 - 6x - {x^2}} }}} \,\,dx = A\sqrt {7 - 6x - {x^2}} + B{\sin ^{ - 1}}\left( {{{x + 3} \over 4}} \right) + C$$
(where C is a constant of integration), then the ordered pair (A, B) is equal to :
A
(2,  1)
B
($$-$$ 2,   $$-$$1)
C
($$-$$ 2,  1)
D
(2,   $$-$$1)

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