1
JEE Main 2018 (Online) 15th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
At the center of a fixed large circular coil of radius R, a much smaller circular coil of radius r is placed. The two coils are concentric and are in the same plane. The larger coil carries a current I. The smaller coil is set to rotate with a constant angular velocity $$\omega $$ about an axis along their common diameter. Calculate the emf induced in their smaller coil after a time t of its start of rotation.
A
$${{{\mu _o}{\rm I}} \over {2\,R}}$$ $$\omega $$ $$\pi $$ r2 sin$$\omega $$ t
B
$${{{\mu _o}{\rm I}} \over {4\,R}}$$ $$\omega $$ $$\pi $$ r2 sin$$\omega $$ t
C
$${{{\mu _o}{\rm I}} \over {4\,R}}$$ $$\omega $$ r2 sin$$\omega $$ t
D
$${{{\mu _o}{\rm I}} \over {2\,R}}$$ $$\omega $$ r2 sin$$\omega $$ t
2
JEE Main 2018 (Online) 15th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A current of 1 A is flowing on the sides of an equilateral triangle of side 4.5 $$ \times $$ 10-2 m. The magnetic field at the center of the triangle will be :
A
2 $$ \times $$ 10-5 Wb/m2
B
Zero
C
8 $$ \times $$ 10-5 Wb/m2
D
4 $$ \times $$ 10-5 Wb/m2
3
JEE Main 2018 (Online) 15th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Truth table for the following digital circuit will be :
JEE Main 2018 (Online) 15th April Evening Slot Physics - Semiconductor Question 166 English
A
JEE Main 2018 (Online) 15th April Evening Slot Physics - Semiconductor Question 166 English Option 1
B
JEE Main 2018 (Online) 15th April Evening Slot Physics - Semiconductor Question 166 English Option 2
C
JEE Main 2018 (Online) 15th April Evening Slot Physics - Semiconductor Question 166 English Option 3
D
JEE Main 2018 (Online) 15th April Evening Slot Physics - Semiconductor Question 166 English Option 4
4
JEE Main 2018 (Online) 15th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
JEE Main 2018 (Online) 15th April Evening Slot Physics - Electromagnetic Induction Question 104 English
A copper rod of mass m slides under gravity on two smooth parallel rails, with separation l and set at an angle of $$\theta $$ with the horizontal. At the bottom rails are joined by a resistance R. There is a uniform magnetic field B normal to the plane of the rails, as shown in the igure. The terminal speed of the copper rod is :
A
$${{mg\,R\,\tan \,\theta } \over {{B^2}\,{l^2}}}$$
B
$${{mg\,R\,\cot \,\theta } \over {{B^2}\,{l^2}}}$$
C
$${{mg\,R\,\sin \,\theta } \over {{B^2}\,{l^2}}}$$
D
$${{mg\,R\,\cos \,\theta } \over {{B^2}\,{l^2}}}$$
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