1
JEE Main 2018 (Online) 15th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The de-Broglie's wavelength of electron present in first Bohr orbit of 'H' atom is :
A
0.529 $$\mathop {\rm A}\limits^ \circ $$
B
2$$\pi $$ $$ \times $$ 0.529 $$\mathop {\rm A}\limits^ \circ $$
C
$${{0.529} \over {2\pi }}$$ $$\mathop {\rm A}\limits^ \circ $$
D
4 $$ \times $$ 0.529 $$\mathop {\rm A}\limits^ \circ $$
2
JEE Main 2018 (Online) 15th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Given

(i)   2Fe2O3(s) $$ \to $$ 4Fe(s) + 3O2(g);

$$\Delta $$rGo = + 1487.0 kJ mol-1

(ii)   2CO(g) + O2(g) $$ \to $$ 2CO2(g);

$$\Delta $$rGo = $$-$$ 514.4 kJ mol-1

Free energy change, $$\Delta $$rGo for the reaction

2Fe2O3(s) + 6CO(g) $$ \to $$ 4Fe(s) + 6CO2(g) will be :
A
$$-$$ 112.4 kJ mol-1
B
$$-$$ 56.2 kJ mol-1
C
$$-$$ 168.2 kJ mol-1
D
$$-$$ 208.0 kJ mol-1
3
JEE Main 2018 (Online) 15th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
$$\Delta $$fGo at 500 K for substance 'S' in liquid state and gaseous state are +100.7 kcl mol-1 and +103 kcal mol-1, respectively. Vapour pressure of liquid 'S' at 500 K is approximately equal to : ( R = 2 cal K-1 mol-1 )
A
0.1 atm
B
1 atm
C
10 atm
D
100 atm
4
JEE Main 2018 (Online) 15th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Following four solutions are prepared by mixing different volumes of NaOH and HCl of different concentrations, pH of which one of them will be equal to 1 ?
A
100 mL $${M \over {10}}$$ HCl + 100 mL $${M \over {10}}$$ NaOH
B
75 mL $${M \over {5}}$$ HCl + 25 mL $${M \over {5}}$$ NaOH
C
60 mL $${M \over {10}}$$ HCl + 40 mL $${M \over {10}}$$ NaOH
D
55 mL $${M \over {10}}$$ HCl + 45 mL $${M \over {10}}$$ NaOH
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