1
JEE Main 2018 (Online) 15th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
$$\Delta $$fGo at 500 K for substance 'S' in liquid state and gaseous state are +100.7 kcl mol-1 and +103 kcal mol-1, respectively. Vapour pressure of liquid 'S' at 500 K is approximately equal to : ( R = 2 cal K-1 mol-1 )
A
0.1 atm
B
1 atm
C
10 atm
D
100 atm
2
JEE Main 2018 (Online) 15th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The increasing order of the acidity of the following carboxylic acids is :
JEE Main 2018 (Online) 15th April Evening Slot Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 253 English
A
I   <   III   <   II   <   IV
B
IV   <   II   <   III   <   I
C
II   <   IV   <   III   <   I
D
III   <   II   <   IV   <   I
3
JEE Main 2018 (Online) 15th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The correct order of spin-only magnetic moments among the following is :
(Atomic number : Mn = 25, Co = 27, Ni = 28, Zn = 30)
A
[ZnCl4]2- > [NiCl4]2- > [CoCl4]2- > [MnCl4]2-
B
[CoCl4]2- > [MnCl4]2- > [NiCl4]2- > [ZnCl4]2-
C
[NiCl4]2- > [CoCl4]2- > [MnCl4]2- > [ZnCl4]2-
D
[MnCl4]2- > [CoCl4]2- > [NiCl4]2- > [ZnCl4]2-
4
JEE Main 2018 (Online) 15th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Given

(i)   2Fe2O3(s) $$ \to $$ 4Fe(s) + 3O2(g);

$$\Delta $$rGo = + 1487.0 kJ mol-1

(ii)   2CO(g) + O2(g) $$ \to $$ 2CO2(g);

$$\Delta $$rGo = $$-$$ 514.4 kJ mol-1

Free energy change, $$\Delta $$rGo for the reaction

2Fe2O3(s) + 6CO(g) $$ \to $$ 4Fe(s) + 6CO2(g) will be :
A
$$-$$ 112.4 kJ mol-1
B
$$-$$ 56.2 kJ mol-1
C
$$-$$ 168.2 kJ mol-1
D
$$-$$ 208.0 kJ mol-1

JEE Main Papers

All year-wise previous year question papers

2023
2021