1
JEE Main 2025 (Online) 7th April Morning Shift
MCQ (Single Correct Answer)
+4
-1

Two charges $q_1$ and $q_2$ are separated by a distance of 30 cm . A third charge $q_3$ initially at ' C ' as shown in the figure, is moved along the circular path of radius 40 cm from C to D . If the difference in potential energy due to movement of $q_3$ from C to D is given by $\frac{q_3 \mathrm{~K}}{4 \pi \epsilon_0}$, the value of K is :

JEE Main 2025 (Online) 7th April Morning Shift Physics - Electrostatics Question 6 English

A
$6 \mathrm{q}_2$
B
$6 \mathrm{q}_1$
C
  $8 \mathrm{q}_1$
D
$\mathrm{8 q_2}$
2
JEE Main 2025 (Online) 4th April Evening Shift
MCQ (Single Correct Answer)
+4
-1

A metallic ring is uniformly charged as shown in figure. AC and BD are two mutually perpendicular diameters. Electric field due to arc $A B$ at ' $O$ ' is ' $E$ ' in magnitude. What would be the magnitude of electric field at ' O ' due to arc ABC ?

JEE Main 2025 (Online) 4th April Evening Shift Physics - Electrostatics Question 3 English
A
2E
B
Zero
C
E/2
D
$\sqrt2$E
3
JEE Main 2025 (Online) 4th April Morning Shift
MCQ (Single Correct Answer)
+4
-1

Two infinite identical charged sheets and a charged spherical body of charge density ' $\rho$ ' are arranged as shown in figure. Then the correct relation between the electrical fields at $\mathrm{A}, \mathrm{B}, \mathrm{C}$ and D points is:

JEE Main 2025 (Online) 4th April Morning Shift Physics - Electrostatics Question 2 English

A
$\left|\vec{E}_A\right|=\left|\vec{E}_B\right| ; \vec{E}_C>\vec{E}_D$
B
$\vec{E}_A=\vec{E}_B ; \vec{E}_C=\vec{E}_D$
C
$\vec{E}_C \neq \vec{E}_D ; \vec{E}_A>\vec{E}_B$
D
$\vec{E}_A>\vec{E}_B ; \vec{E}_C=\vec{E}_D$
4
JEE Main 2025 (Online) 4th April Morning Shift
MCQ (Single Correct Answer)
+4
-1

Two small spherical balls of mass 10 g each with charges $-2 \mu \mathrm{C}$ and $2 \mu \mathrm{C}$, are attached to two ends of very light rigid rod of length 20 cm . The arrangement is now placed near an infinite nonconducting charge sheet with uniform charge density of $100 \mu \mathrm{C} / \mathrm{m}^2$ such that length of rod makes an angle of $30^{\circ}$ with electric field generated by charge sheet. Net torque acting on the rod is: (Take $\varepsilon_{\mathrm{o}}: 8.85 \times 10^{-12} \mathrm{C}^2 / \mathrm{Nm}^2$ )

A
1.12 Nm
B
2.24 Nm
C
11.2 Nm
D
112 Nm
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