JEE Main 2019 (Online) 11th January Evening Slot | Electrostatics Question 160 | Physics

An electric field of 1000 V/m is applied to an electric dipole at angle of 45^o. The value of electric dipole moment is 10^–29 C.m. What is the potential energy of the electric dipole?

- 7 $$ \times $$ 10^–27 J

$$-$$ 9 $$ \times $$ 10^–20 J

$$-$$ 10 $$ \times $$ 10^–29 J

$$-$$ 20 $$ \times $$ 10^–18 J

JEE Main 2019 (Online) 11th January Morning Slot

MCQ (Single Correct Answer)

-1

Three charges Q, + q and + q are placed at the vertices of a right-angle isosceles triangle as shown below. The net electrostatic energy of the configuration is zero, if the value of Q is :

JEE Main 2019 (Online) 11th January Morning Slot Physics - Electrostatics Question 162 English

JEE Main 2019 (Online) 11th January Morning Slot Physics - Electrostatics Question 162 English

$${{ - q} \over {1 + \sqrt 2 }}$$

+ q

$$-$$ 2q

$${{ - \sqrt 2 q} \over {\sqrt 2 + 1}}$$

JEE Main 2019 (Online) 11th January Morning Slot

MCQ (Single Correct Answer)

-1

The given graph shows variation (with distance r form centre) of :

JEE Main 2019 (Online) 11th January Morning Slot Physics - Electrostatics Question 161 English

JEE Main 2019 (Online) 11th January Morning Slot Physics - Electrostatics Question 161 English

Electric field of a uniformly charged sphere

Electric field of a uniformly charged spherical shell

Potential of a uniformly charged sphere

Potential of a uniformly charged spherical shell

JEE Main 2019 (Online) 10th January Evening Slot

MCQ (Single Correct Answer)

-1

Four equal point charges Q each are placed in the xy plane at (0, 2), (4, 2), (4, –2) and (0, –2). The work required to put a fifth charge Q at the origin of the coordinate system will be -

$${{{Q_2}} \over {4\pi {\varepsilon _0}}}$$

$${{{Q^2}} \over {2\sqrt 2 \pi {\varepsilon _0}}}$$

$${{{Q_2}} \over {4\pi {\varepsilon _0}}}\left( {1 + {1 \over {\sqrt 3 }}} \right)$$

$${{{Q_2}} \over {4\pi {\varepsilon _0}}}\left( {1 + {1 \over {\sqrt 5 }}} \right)$$

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