1
JEE Main 2024 (Online) 8th April Evening Shift
MCQ (Single Correct Answer)
+4
-1

A thin circular disc of mass $$\mathrm{M}$$ and radius $$\mathrm{R}$$ is rotating in a horizontal plane about an axis passing through its centre and perpendicular to its plane with angular velocity $$\omega$$. If another disc of same dimensions but of mass $$\mathrm{M} / 2$$ is placed gently on the first disc co-axially, then the new angular velocity of the system is :

A
$$\frac{4}{5} \omega$$
B
$$\frac{5}{4} \omega$$
C
$$\frac{3}{2} \omega$$
D
$$\frac{2}{3} \omega$$
2
JEE Main 2024 (Online) 5th April Morning Shift
MCQ (Single Correct Answer)
+4
-1

Ratio of radius of gyration of a hollow sphere to that of a solid cylinder of equal mass, for moment of Inertia about their diameter axis $$A B$$ as shown in figure is $$\sqrt{8 / x}$$. The value of $$x$$ is :

JEE Main 2024 (Online) 5th April Morning Shift Physics - Rotational Motion Question 3 English

A
34
B
51
C
67
D
17
3
JEE Main 2024 (Online) 1st February Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
A disc of radius $\mathrm{R}$ and mass $\mathrm{M}$ is rolling horizontally without slipping with speed $v$. It then moves up an inclined smooth surface as shown in figure. The maximum height that the disc can go up the incline is :

JEE Main 2024 (Online) 1st February Evening Shift Physics - Rotational Motion Question 20 English
A
$\frac{3}{4} \frac{v^2}{\mathrm{~g}}$
B
$\frac{v^2}{g}$
C
$\frac{2}{3} \frac{v^2}{\mathrm{~g}}$
D
$\frac{1}{2} \frac{v^2}{\mathrm{~g}}$
4
JEE Main 2024 (Online) 30th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

A particle of mass $$\mathrm{m}$$ is projected with a velocity '$$\mathrm{u}$$' making an angle of $$30^{\circ}$$ with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height $$\mathrm{h}$$ is :

A
$$\frac{\mathrm{mu}^3}{\sqrt{2} \mathrm{~g}}$$
B
zero
C
$$\frac{\sqrt{3}}{2} \frac{\mathrm{mu}^2}{\mathrm{~g}}$$
D
$$\frac{\sqrt{3}}{16} \frac{\mathrm{mu}^3}{\mathrm{~g}}$$
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