AIEEE 2005 | Electrostatics Question 243 | Physics

Two thin wire rings each having a radius $$R$$ are placed at a distance $$d$$ apart with their axes coinciding. The charges on the two rings are $$+q$$ and $$-q.$$ The potential difference between the centres of the two rings is

$${q \over {2\pi \,{ \in _0}}}\left[ {{1 \over R} - {1 \over {\sqrt {{R^2} + {d^2}} }}} \right]$$

$${{qR} \over {4\pi \,{ \in _0}\,{d^2}}}$$

$${q \over {4\pi \,{ \in _0}}}\left[ {{1 \over R} - {1 \over {\sqrt {{R^2} + {d^2}} }}} \right]$$

zero

AIEEE 2005

MCQ (Single Correct Answer)

-1

Two point charges $$+8q$$ and $$-2q$$ are located at $$x=0$$ and $$x=L$$ respectively. The location of a point on the $$x$$ axis at which the net electric field due to these two point charges is zero is

$${L \over 4}$$

$$2$$ $$L$$

$$4$$ $$L$$

$$8$$ $$L$$

AIEEE 2004

MCQ (Single Correct Answer)

-1

Two spherical conductors $$B$$ and $$C$$ having equal radii and carrying equal charges on them repel each other with a force $$F$$ when kept apart at some distance. A third spherical conductor having same radius as that $$B$$ but uncharged is brought in contact with $$B,$$ then brought in correct with $$C$$ and finally removed away from both. The new force of repulsion between $$B$$ and $$C$$ is

$$F/8$$

$$3$$ $$F/4$$

$$F/4$$

$$3$$ $$F/8$$

AIEEE 2004

MCQ (Single Correct Answer)

-1

A charge particle $$'q'$$ is shot towards another charged particle $$'Q'$$ which is fixed, with a speed $$'v'$$. It approaches $$'Q'$$ upto a closest distance $$r$$ and then returns. If $$q$$ were given a speed of $$'2v'$$ the closest distances of approaches would be

$$r/2$$

$$2r$$

$$r$$

$$r/4$$

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