JEE Main 2020 (Online) 3rd September Evening Slot | Electrostatics Question 90 | Physics

JEE Main 2020 (Online) 3rd September Evening Slot

MCQ (Single Correct Answer)

-1

Concentric metallic hollow spheres of radii R and 4R hold charges Q₁ and Q₂ respectively. Given that surface charge densities of the concentric spheres are equal, the potential difference V(R) – V(4R) is :

$${{3{Q_2}} \over {4\pi {\varepsilon _0}R}}$$

$${{3{Q_1}} \over {4\pi {\varepsilon _0}R}}$$

$${{3{Q_1}} \over {16\pi {\varepsilon _0}R}}$$

$${{{Q_2}} \over {4\pi {\varepsilon _0}R}}$$

JEE Main 2020 (Online) 3rd September Morning Slot

MCQ (Single Correct Answer)

-1

Two isolated conducting spheres S₁ and S₂ of radius $${2 \over 3}R$$ and $${1 \over 3}R$$ have 12 $$\mu $$C and –3 $$\mu $$C charges, respectively, and are at a large distance from each other. They are now connected by a conducting wire. A long time after this is done the charges on S₁ and S₂ are respectively :

4.5 $$\mu $$C on both

+4.5 $$\mu $$C and –4.5 $$\mu $$C

6 $$\mu $$C and 3 $$\mu $$C

3 $$\mu $$C and 6 $$\mu $$C

JEE Main 2020 (Online) 2nd September Evening Slot

MCQ (Single Correct Answer)

-1

A charge Q is distributed over two concentric conducting thin spherical shells radii r and R (R > r). If the surface charge densities on the two shells are equal, the electric potential at the common centre is : JEE Main 2020 (Online) 2nd September Evening Slot Physics - Electrostatics Question 90 English

JEE Main 2020 (Online) 2nd September Evening Slot Physics - Electrostatics Question 90 English

$${1 \over {4\pi {\varepsilon _0}}}{{\left( {R + r} \right)} \over {\left( {{R^2} + {r^2}} \right)}}$$Q

$${1 \over {4\pi {\varepsilon _0}}}{{\left( {R + r} \right)} \over {2\left( {{R^2} + {r^2}} \right)}}Q$$

$${1 \over {4\pi {\varepsilon _0}}}{{\left( {R + 2r} \right)Q} \over {2\left( {{R^2} + {r^2}} \right)}}$$

$${1 \over {4\pi {\varepsilon _0}}}{{\left( {2R + r} \right)} \over {\left( {{R^2} + {r^2}} \right)}}Q$$

JEE Main 2020 (Online) 2nd September Morning Slot

MCQ (Single Correct Answer)

-1

A charged particle (mass m and charge q)
moves along X-axis with velocity V₀. When it
passes through the origin it enters a region having uniform electric field
$$\overrightarrow E = - E\widehat j$$ which extends upto x = d.
Equation of path of electron in the region x > d is JEE Main 2020 (Online) 2nd September Morning Slot Physics - Electrostatics Question 91 English