JEE Main 2020 (Online) 7th January Morning Slot | Electrostatics Question 209 | Physics

JEE Main 2020 (Online) 7th January Morning Slot

MCQ (Single Correct Answer)

-1

Two infinite planes each with uniform surface charge density to are kept in such a way that the angle between them is 30^o. The electric field in the region shown between them is given by : JEE Main 2020 (Online) 7th January Morning Slot Physics - Electrostatics Question 209 English

JEE Main 2020 (Online) 7th January Morning Slot Physics - Electrostatics Question 209 English

$${\sigma \over {{ \in _0}}}\left[ {\left( {1 + {{\sqrt 3 } \over 2}} \right)\widehat y + {{\widehat x} \over 2}} \right]$$

$${\sigma \over {2{ \in _0}}}\left[ {\left( {1 + \sqrt 3 } \right)\widehat y + {{\widehat x} \over 2}} \right]$$

$${\sigma \over {2{ \in _0}}}\left[ {\left( {1 + \sqrt 3 } \right)\widehat y - {{\widehat x} \over 2}} \right]$$

$${\sigma \over {2{ \in _0}}}\left[ {\left( {1 - {{\sqrt 3 } \over 2}} \right)\widehat y - {{\widehat x} \over 2}} \right]$$

JEE Main 2019 (Online) 12th April Evening Slot

MCQ (Single Correct Answer)

-1

Let a total charge 2Q be distributed in a sphere of radius R, with the charge density given by $$\rho $$(r) = kr, where r is the distance from the centre. Two charges A and B, of –Q each, are placed on diametrically opposite points, at equal distance, $$a$$ from the centre. If A and B do not experience any force, then :

$$a = {8^{ - 1/4}}R$$

$$a = {2^{ - 1/4}}R$$

$$a = {{3R} \over {{2^{1/4}}}}$$

$$a = {R \over {\sqrt 3 }}$$

JEE Main 2019 (Online) 12th April Morning Slot

MCQ (Single Correct Answer)

-1

A point dipole $$\overrightarrow p = - {p_0}\widehat x$$ is kept at the origin. The potential and electric field due to this dipole on the y-axis at a distance d are, respectively: (Take V= 0 at infinity)

$${{\left| {\overrightarrow p } \right|} \over {4\pi { \in _0}{d^2}}},{{ - \overrightarrow p } \over {4\pi { \in _0}{d^3}}}$$

$$0,{{\overrightarrow p } \over {4\pi { \in _0}{d^3}}}$$

$${{\left| {\overrightarrow p } \right|} \over {4\pi { \in _0}{d^2}}},{{\overrightarrow p } \over {4\pi { \in _0}{d^3}}}$$

$$0,{{ - \overrightarrow p } \over {4\pi { \in _0}{d^3}}}$$

JEE Main 2019 (Online) 12th April Morning Slot

MCQ (Single Correct Answer)

-1

Shown in the figure is a shell made of a conductor. It has inner radius a and outer radius b, and carries charge Q. At its centre is a dipole $$\overrightarrow P $$ as shown. In this case : JEE Main 2019 (Online) 12th April Morning Slot Physics - Electrostatics Question 212 English

JEE Main 2019 (Online) 12th April Morning Slot Physics - Electrostatics Question 212 English

surface charge density on the inner surface is uniform and equal to $${{\left( {Q/2} \right)} \over {4\pi {a^2}}}$$

surface charge density on the inner surface of the shell is zero everywhere

surface charge density on the outer surface depends on $$\left| {\overrightarrow P } \right|$$

electric field outside the shell is the same as that of a point charge at the centre of the shell

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