### JEE Mains Previous Years Questions with Solutions

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### AIEEE 2002

On moving a charge of $20$ coulomb by $2$ $cm,$ $2$ $J$ of work is done, then the potential differences between the points is
A
$0.1$ $V$
B
$8$ $V$
C
$2V$
D
$0.5$ $V.$

## Explanation

We know that ${{{W_{AB}}} \over q} = {V_B} - {V_A}$

$\therefore$ ${V_B} - {V_A} = {{2J} \over {20C}} = 0.11J/C = 0.1V$