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JEE Main 2026 (Online) 6th April Evening Shift
Numerical
+4
-1
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Two cells of emfs 1 V and 2 V and internal resistance $2 \Omega$ and $1 \Omega$, respectively connected in parallel, gave a current of 1 A through an external resistance. If the polarity of one cell is reversed, then value of current through the external resistance will be $\frac{\alpha}{5} \mathrm{~A}$. The value of $\alpha$ is $\_\_\_\_$.

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2
JEE Main 2026 (Online) 6th April Morning Shift
Numerical
+4
-1
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Refer to the circuit diagram given below. The heat generated across the $6 \Omega$ resistance in 100 second is $\frac{\alpha}{100} \mathrm{~J}$. The value of $\alpha$ is $\_\_\_\_$ . (Nearest integer)

JEE Main 2026 (Online) 6th April Morning Shift Physics - Current Electricity Question 3 English
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3
JEE Main 2026 (Online) 5th April Evening Shift
Numerical
+4
-1
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When an external resistance of $5 \Omega$ is connected across terminals of a cell, a current of 0.25 A flows through it. When the $5 \Omega$ resistor is replaced by a $2 \Omega$ resistor, a current of 0.5 A flows through it. The internal resistance of the cell is $\_\_\_\_$ $\Omega$.

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4
JEE Main 2026 (Online) 28th January Morning Shift
Numerical
+4
-1
Change Language

The equivalent resistance between the points $A$ and $B$ in the following circuit is $\frac{x}{5} \Omega$. The value of $x$ is $\_\_\_\_$ .

JEE Main 2026 (Online) 28th January Morning Shift Physics - Current Electricity Question 22 English
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