JEE Main 2014 (Offline) | Trigonometric Functions & Equations Question 83 | Mathematics

JEE Main 2014 (Offline)

MCQ (Single Correct Answer)

-1

Let $$fk\left( x \right) = {1 \over k}\left( {{{\sin }^k}x + {{\cos }^k}x} \right)$$ where $$x \in R$$ and $$k \ge \,.$$
Then $${f_4}\left( x \right) - {f_6}\left( x \right)\,\,$$ equals

$${1 \over 4}$$

$${1 \over 12}$$

$${1 \over 6}$$

$${1 \over 3}$$

JEE Main 2013 (Offline)

MCQ (Single Correct Answer)

-1

The expression $${{\tan {\rm A}} \over {1 - \cot {\rm A}}} + {{\cot {\rm A}} \over {1 - \tan {\rm A}}}$$ can be written as:

$$\sin {\rm A}\,\cos {\rm A} + 1$$

$$\,\sec {\rm A}\,\cos ec{\rm A} + 1$$

$$\tan {\rm A} + \cot {\rm A}$$

$$\sec {\rm A} + \cos ec{\rm A}$$

JEE Main 2013 (Offline)

MCQ (Single Correct Answer)

-1

$$ABCD$$ is a trapezium such that $$AB$$ and $$CD$$ are parallel and $$BC \bot CD.$$ If $$\angle ADB = \theta ,\,BC = p$$ and $$CD = q,$$ then AB is equal to:

$${{\left( {{p^2} + {q^2}} \right)\sin \theta } \over {p\cos \theta + q\sin \theta }}$$

$${{{p^2} + {q^2}\cos \theta } \over {p\cos \theta + q\sin \theta }}$$

$${{{p^2} + {q^2}} \over {{p^2}\cos \theta + {q^2}\sin \theta }}$$

$${{\left( {{p^2} + {q^2}} \right)\sin \theta } \over {{{\left( {p\cos \theta + q\sin \theta } \right)}^2}}}$$

AIEEE 2012

MCQ (Single Correct Answer)

-1

In a $$\Delta PQR,{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} $$ If $$3{\mkern 1mu} \sin {\mkern 1mu} P + 4{\mkern 1mu} \cos {\mkern 1mu} Q = 6$$ and $$4\sin Q + 3\cos P = 1,$$ then the angle R is equal to :

$${{5\pi } \over 6}$$

$${{\pi } \over 6}$$

$${{\pi } \over 4}$$

$${{3\pi } \over 4}$$

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