1
JEE Main 2020 (Online) 5th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
In the circuit, given in the figure currents in different branches and value of one resistor are shown. Then potential at point B with respect to the point A is : JEE Main 2020 (Online) 5th September Evening Slot Physics - Current Electricity Question 247 English
A
+2 V
B
-2 V
C
+1 V
D
-1 V
2
JEE Main 2020 (Online) 5th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The correct match between the entries in column I and column II are :

I II
Radiation Wavelength
(a) Microwave (i) 100 m
(b) Gamma rays (ii) 10–15 m
(c) A.M. radio waves (iii) 10–10 m
(d) X-rays (iv) 10–3 m
A
(a)-(ii), (b)-(i), (c)-(iv), (d)-(iii)
B
(a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)
C
(a)-(iii), (b)-(ii), (c)-(i), (d)-(iv)
D
(a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)
3
JEE Main 2020 (Online) 5th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Ten charges are placed on the circumference of a circle of radius R with constant angular separation between successive charges. Alternate charges 1, 3, 5, 7, 9 have charge (+q) each, while 2, 4, 6, 8, 10 have charge (–q) each. The potential V and the electric field E at the centre of the circle are respectively.
(Take V = 0 at infinity)
A
V = 0; E = 0
B
$$V = {{10q} \over {4\pi {\varepsilon _0}R}}$$; $$E = {{10q} \over {4\pi {\varepsilon _0}{R^2}}}$$
C
$$V = {{10q} \over {4\pi {\varepsilon _0}R}}$$; E = 0
D
V = 0; $$E = {{10q} \over {4\pi {\varepsilon _0}{R^2}}}$$
4
JEE Main 2020 (Online) 5th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
In the circuit shown, charge on the 5 $$\mu $$F capacitor is :

JEE Main 2020 (Online) 5th September Evening Slot Physics - Capacitor Question 113 English
A
5.45 $$\mu $$C
B
18.00 $$\mu $$C
C
10.90 $$\mu $$C
D
16.36 $$\mu $$C

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