1
JEE Main 2020 (Online) 5th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
An infinitely long, straight wire carrying current I, one side opened rectangular loop and a conductor C with a sliding connector are located in the same plane, as shown, in the figure. The connector has length $$l$$ and resistance R. It slides to the right with a velocity v. The resistance of the conductor and the self inductance of the loop are negligible. The induced current in the loop, as a function of separation r, between the connector and the straight wire is : JEE Main 2020 (Online) 5th September Evening Slot Physics - Electromagnetic Induction Question 102 English
A
$${{{\mu _0}} \over {4\pi }}{{Ivl} \over {Rr}}$$
B
$${{{\mu _0}} \over {\pi }}{{Ivl} \over {Rr}}$$
C
$${{{\mu _0}} \over {2\pi }}{{Ivl} \over {Rr}}$$
D
$${{2{\mu _0}} \over \pi }{{Ivl} \over {Rr}}$$
2
JEE Main 2020 (Online) 5th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
An iron rod of volume 10–3 m3 and relative permeability 1000 is placed as core in a solenoid with 10 turns/cm. If a current of 0.5 A is passed through the solenoid, then the magnetic moment of the rod will be :
A
5 $$ \times $$ 102 Am2
B
0.5 $$ \times $$ 102 Am2
C
500 $$ \times $$ 102 Am2
D
50 $$ \times $$ 102 Am2
3
JEE Main 2020 (Online) 5th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
In an experiment to verify Stokes law, a small spherical ball of radius r and density $$\rho $$ falls under gravity through a distance h in air before entering a tank of water. If the terminal velocity of the ball inside water is same as its velocity just before entering the water surface, then the value of h is proportional to :
(ignore viscosity of air)
A
r
B
r4
C
r3
D
r2
4
JEE Main 2020 (Online) 5th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A spaceship in space sweeps stationary interplanetary dust. As a result, its mass
increases at a rate $${{dM\left( t \right)} \over {dt}}$$ = bv2(t), where v(t) is its instantaneous velocity. The instantaneous acceleration of the satellite is :
A
-bv3(t)
B
$$ - {{2b{v^3}} \over {M\left( t \right)}}$$
C
$$ - {{b{v^3}} \over {M\left( t \right)}}$$
D
$$ - {{b{v^3}} \over {2M\left( t \right)}}$$

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