1
JEE Main 2020 (Online) 5th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The major product formed in the following reaction is :
CH3CH = CHCH(CH3)2 $$\buildrel {HBr} \over \longrightarrow $$
A
Br(CH2)3CH(CH3)2
B
CH3CH(Br)CH2CH(CH3)2
C
CH3CH2CH(Br)CH(CH3)2
D
CH3CH2CH2C(Br)(CH3)2
2
JEE Main 2020 (Online) 5th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The value of $${\left( {{{ - 1 + i\sqrt 3 } \over {1 - i}}} \right)^{30}}$$ is :
A
–215i
B
–215
C
215i
D
65
3
JEE Main 2020 (Online) 5th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If the mean and the standard deviation of the
data 3, 5, 7, a, b are 5 and 2 respectively, then a and b are the roots of the equation :
A
x2 – 20x + 18 = 0
B
2x2 – 20x + 19 = 0
C
x2 – 10x + 18 = 0
D
x2 – 10x + 19 = 0
4
JEE Main 2020 (Online) 5th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If L = sin2$$\left( {{\pi \over {16}}} \right)$$ - sin2$$\left( {{\pi \over {8}}} \right)$$ and
M = cos2$$\left( {{\pi \over {16}}} \right)$$ - sin2$$\left( {{\pi \over {8}}} \right)$$, then :
A
L = $$ - {1 \over {2\sqrt 2 }} + {1 \over 2}\cos {\pi \over 8}$$
B
M = $${1 \over {2\sqrt 2 }} + {1 \over 2}\cos {\pi \over 8}$$
C
M = $${1 \over {4\sqrt 2 }} + {1 \over 4}\cos {\pi \over 8}$$
D
L = $${1 \over {4\sqrt 2 }} - {1 \over 4}\cos {\pi \over 8}$$

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