1
JEE Main 2020 (Online) 5th September Evening Slot
Numerical
+4
-0
Change Language
A thin rod of mass 0.9 kg and length 1 m is suspended, at rest, from one end so that it can freely oscillate in the vertical plane. A particle of move 0.1 kg moving in a straight line with velocity 80 m/s hits the rod at its bottom most point and sticks to it (see figure). The angular speed (in rad/s) of the rod immediately after the collision will be _________. JEE Main 2020 (Online) 5th September Evening Slot Physics - Rotational Motion Question 134 English
Your input ____
2
JEE Main 2020 (Online) 5th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
In the circuit, given in the figure currents in different branches and value of one resistor are shown. Then potential at point B with respect to the point A is : JEE Main 2020 (Online) 5th September Evening Slot Physics - Current Electricity Question 221 English
A
+2 V
B
-2 V
C
+1 V
D
-1 V
3
JEE Main 2020 (Online) 5th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Two Zener diodes (A and B) having breakdown voltages of 6 V and 4 V respectively, are connected as shown in the circuit below. The output voltage V0 variation with input voltage linearly increasing with time, is given by :
(Vinput = 0 V at t = 0)
(figures are qualitative) JEE Main 2020 (Online) 5th September Evening Slot Physics - Semiconductor Question 141 English
A
JEE Main 2020 (Online) 5th September Evening Slot Physics - Semiconductor Question 141 English Option 1
B
JEE Main 2020 (Online) 5th September Evening Slot Physics - Semiconductor Question 141 English Option 2
C
JEE Main 2020 (Online) 5th September Evening Slot Physics - Semiconductor Question 141 English Option 3
D
JEE Main 2020 (Online) 5th September Evening Slot Physics - Semiconductor Question 141 English Option 4
4
JEE Main 2020 (Online) 5th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Two different wires having lengths L1 and L2, and respective temperature coefficient of linear expansion $$\alpha $$1 and $$\alpha $$2, are joined end-to-end. Then the effective temperature coefficient of linear expansion is :
A
$$2\sqrt {{\alpha _1}{\alpha _2}} $$
B
$$4{{{\alpha _1}{\alpha _2}} \over {{\alpha _1} + {\alpha _2}}}{{{L_2}{L_1}} \over {{{\left( {{L_2} + {L_1}} \right)}^2}}}$$
C
$${{{\alpha _1} + {\alpha _2}} \over 2}$$
D
$${{{\alpha _1}{L_1} + {\alpha _2}{L_2}} \over {{L_1} + {L_2}}}$$
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