1
AIEEE 2012
MCQ (Single Correct Answer)
+4
-1
Proton, deuteron and alpha particle of same kinetic energy are moving in circular trajectories in a constant magnetic field. The radii of proton, denuteron and alpha particle are respectively $${r_p},{r_d}$$ and $${r_\alpha }$$. Which one of the following relation is correct?
A
$${r_\alpha } = {r_p} = {r_d}$$
B
$${r_\alpha } = {r_p} < {r_d}$$
C
$${r_\alpha } > {r_d} > {r_p}$$
D
$${r_\alpha } = {r_d} > {r_p}$$
2
AIEEE 2012
MCQ (Single Correct Answer)
+4
-1
A charge $$Q$$ is uniformly distributed over the surface of non-conducting disc of radius $$R.$$ The disc rotates about an axis perpendicular to its plane and passing through its center with an angular velocity $$\omega .$$ As a result of this rotation a magnetic field of induction $$B$$ is obtained at the center of the disc. If we keep both the amount of charge placed on the disc and its angular velocity to be constant and very the radius of the disc then the variation of the magnetic induction at the center of the disc will be represented by the figure :
A
AIEEE 2012 Physics - Magnetic Effect of Current Question 163 English Option 1
B
AIEEE 2012 Physics - Magnetic Effect of Current Question 163 English Option 2
C
AIEEE 2012 Physics - Magnetic Effect of Current Question 163 English Option 3
D
AIEEE 2012 Physics - Magnetic Effect of Current Question 163 English Option 4
3
AIEEE 2012
MCQ (Single Correct Answer)
+4
-1
A coil is suspended in a uniform magnetic field, with the plane of the coil parallel to the magnetic lines of force. When a current is passed through the coil it starts oscillating; It is very difficult to stop. But if an aluminium plate is placed near to the coil, it stops. This is due to :
A
development of air current when the plate is placed
B
induction of electrical charge on the plate
C
shielding of magnetic lines of force as aluminium is a para-magnetic material.
D
electromagnetic induction in the aluminium plate giving rise to electromagnetic damping.
4
AIEEE 2012
MCQ (Single Correct Answer)
+4
-1
In Young's double slit experiment , one of the slit is wider than other, so that amplitude of the light from one slit is double of that from other slit. If $${{\rm I}_m}$$ be the maximum intensity, the resultant intensity $${\rm I}$$ when they interfere at phase difference $$\phi $$ is given by :
A
$${{{I_m}} \over 9}\left( {4 + 5\cos \,\phi } \right)$$
B
$${{{I_m}} \over 3}\left( {1 + 2{{\cos }^2}\,{\phi \over 2}} \right)$$
C
$${{{I_m}} \over 3}\left( {1 + 4{{\cos }^2}\,{\phi \over 2}} \right)$$
D
$${{{I_m}} \over 9}\left( {1 + 8{{\cos }^2}\,{\phi \over 2}} \right)$$
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