1
AIEEE 2012
MCQ (Single Correct Answer)
+4
-1
Two electric bulbs marked $$25W$$ $$-$$ $$220$$ $$V$$ and $$100W$$ $$-$$ $$220V$$ are connected in series to a $$440$$ $$V$$ supply. Which of the bulbs will fuse?
A
Both
B
$$100$$ $$W$$
C
$$25$$ $$W$$
D
Neither
2
AIEEE 2012
MCQ (Single Correct Answer)
+4
-1
This question has statement- $$1$$ and statement- $$2.$$ Of the four choices given after the statements, choose the one that best describe the two statements.
An insulating solid sphere of radius $$R$$ has a uniformly positive charge density $$\rho $$. As a result of this uniform charge distribution there is a finite value of electric potential at the center of the sphere, at the surface of the sphere and also at a point out side the sphere. The electric potential at infinite is zero.

Statement- $$1:$$ When a charge $$q$$ is take from the centre of the surface of the sphere its potential energy changes by $${{q\rho } \over {3{\varepsilon _0}}}$$
Statement- $$2:$$ The electric field at a distance $$r\left( {r < R} \right)$$ from the center of the sphere is $${{\rho r} \over {3{\varepsilon _0}}}.$$

A
Statement- $$1$$ is true, Statement- $$2$$ is true; Statement- $$2$$ is not the correct explanation of Statement- $$1$$.
B
Statement $$1$$ is true, Statement $$2$$ is false.
C
Statement $$1$$ is false, Statement $$2$$ is true.
D
Statement- $$1$$ is true, Statement- $$2$$ is true; Statement- $$2$$ is the correct explanation of Statement- $$1$$.
3
AIEEE 2012
MCQ (Single Correct Answer)
+4
-1
In a uniformly charged sphere of total charge $$Q$$ and radius $$R,$$ the electric field $$E$$ is plotted as function of distance from the center. The graph which would correspond to the above will be:
A
AIEEE 2012 Physics - Electrostatics Question 188 English Option 1
B
AIEEE 2012 Physics - Electrostatics Question 188 English Option 2
C
AIEEE 2012 Physics - Electrostatics Question 188 English Option 3
D
AIEEE 2012 Physics - Electrostatics Question 188 English Option 4
4
AIEEE 2012
MCQ (Single Correct Answer)
+4
-1
A cylindrical tube, open at both ends, has a fundamental frequency, $$f,$$ in air. The tube is dipped vertically in water so that half of it is in water. The fundamental frequency of the air-column is now :
A
$$f$$
B
$$f/2$$
C
$$3/4$$
D
$$2f$$
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