AIEEE 2007 | Electrochemistry Question 158 | Chemistry

The equivalent conductances of two strong electrolytes at infinite dilution in H₂O (where ions move freely through a solution) at 25^oC are given below:
$$ \wedge _{C{H_3}COONa}^o$$ = 91.0 S cm²/equiv
$$ \wedge _{HCl}^o$$ = 426.2 S cm²/equiv
What additional information/quantity one needs to calculate $$ \wedge ^o$$ of an aqueous solution of acetic acid?

$$ \wedge ^o$$ of chloroacetic acid (C/CH₂COOH)

$$ \wedge ^o$$ of NaCl

$$ \wedge ^o$$ of CH₃COOK

The limiting equivalent conductance of $${H^ + }( \wedge _{{H^ + }}^o)$$

AIEEE 2007

MCQ (Single Correct Answer)

-1

The cell, Zn | Zn²⁺ (1M) || Cu²⁺ (1M) | Cu($$E_{cell}^o$$ = 1.10V) was allowed to be completely discharged at 298 K. The relative concentration of Zn²⁺ to Cu²⁺ $$\left[ {{{\left[ {Z{n^{2 + }}} \right]} \over {\left[ {C{u^{2 + }}} \right]}}} \right]$$ is

antilog (24.08)

37.3

10^37.3

9.65 $$\times$$ 10⁴

AIEEE 2006

MCQ (Single Correct Answer)

-1

The molar conductivities $$ \wedge _{NaOAc}^o$$ and $$ \wedge _{HCl}^o$$ and at infinite dilution in water at 25^oC are 91.0 and 426.2 Scm²/mol respectively. To calculate $$ \wedge _{HOAc}^o$$ , the additional value required is

$$ \wedge _{{H_2}O}^o$$

$$ \wedge _{KCl}^o$$

$$ \wedge _{NaOH}^o$$

$$ \wedge _{NaCl}^o$$

AIEEE 2006

MCQ (Single Correct Answer)

-1

Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1 M is 100$$\Omega $$. The conductivity of this solution is 1.29 S m^–1. Resistance of the same cell when filled with 0.2 M of the same solution is 520 $$\Omega $$, The molar conductivity of 0.02 M solution of the electrolyte will be

124 $$\times$$ 10^–4 S m² mol^–1

1240 $$\times$$ 10^–4 S m² mol^–1

1.24 $$\times$$ 10^–4 S m² mol^–1

12.4 $$\times$$ 10^–4 S m² mol^–1

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