JEE Main 2020 (Online) 4th September Morning Slot | Electrochemistry Question 109 | Chemistry

JEE Main 2020 (Online) 4th September Morning Slot

MCQ (Single Correct Answer)

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JEE Main 2020 (Online) 4th September Morning Slot Chemistry - Electrochemistry Question 110 English

$$E_{C{u^{2 + }}|Cu}^0$$ = +0.34 V

$$E_{Z{n^{2 + }}|Zn}^0$$ = -0.76 V

Identify the incorrect statement from the option below for the above cell :

If E_ext < 1.1 V, Zn dissolves at anode and Cu deposits at cathode

If E_ext = 1.1 V, no flow of e^– or current occurs

If E_ext > 1.1 V, e^– flows from Cu to Zn

If E_ext > 1.1 V, Zn dissolves at Zn electrode and Cu deposits at Cu electrode

JEE Main 2020 (Online) 3rd September Morning Slot

MCQ (Single Correct Answer)

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Let C_NaCl and C_BaSO₄ be the conductances (in S) measured for saturated aqueous solutions of NaCl and BaSO₄, respectively, at a temperature T. Which of the following is false?

Ionic mobilities of ions from both salts increase with T.

C_NaCl(T₂) > C_NaCl(T₁) for T₂ > T₁

C_BaSO₄(T₂) > C_BaSO₄(T₁) for T₂ > T₁

C_NaCl >> C_BaSO₄ at a given T

JEE Main 2020 (Online) 7th January Evening Slot

MCQ (Single Correct Answer)

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The equation that is incorrect is :

$${\left( {\Lambda _m^0} \right)_{KCl}} - {\left( {\Lambda _m^0} \right)_{NaCl}} = {\left( {\Lambda _m^0} \right)_{KBr}} - {\left( {\Lambda _m^0} \right)_{NaBr}}$$

$${\left( {\Lambda _m^0} \right)_{NaBr}} - {\left( {\Lambda _m^0} \right)_{NaI}} = {\left( {\Lambda _m^0} \right)_{KBr}} - {\left( {\Lambda _m^0} \right)_{NaBr}}$$

$${\left( {\Lambda _m^0} \right)_{NaBr}} - {\left( {\Lambda _m^0} \right)_{NaCl}} = {\left( {\Lambda _m^0} \right)_{KBr}} - {\left( {\Lambda _m^0} \right)_{KCl}}$$

$${\left( {\Lambda _m^0} \right)_{{H_2}O}} = {\left( {\Lambda _m^0} \right)_{HCl}} + {\left( {\Lambda _m^0} \right)_{NaOH}} - {\left( {\Lambda _m^0} \right)_{NaCl}}$$

JEE Main 2020 (Online) 7th January Morning Slot

MCQ (Single Correct Answer)

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Given that the standard potentials (E^o) of Cu²⁺/Cu and Cu⁺/Cu are 0.34 V and 0.522 V respectively, the E^o of Cu²⁺/Cu⁺ :

- 0.182 V

- 0.158 V

0.182 V

+0.158 V

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