JEE Main 2020 (Online) 3rd September Morning Slot | Electrochemistry Question 111 | Chemistry

JEE Main 2020 (Online) 3rd September Morning Slot

MCQ (Single Correct Answer)

-1

Let C_NaCl and C_BaSO₄ be the conductances (in S) measured for saturated aqueous solutions of NaCl and BaSO₄, respectively, at a temperature T. Which of the following is false?

Ionic mobilities of ions from both salts increase with T.

C_NaCl(T₂) > C_NaCl(T₁) for T₂ > T₁

C_BaSO₄(T₂) > C_BaSO₄(T₁) for T₂ > T₁

C_NaCl >> C_BaSO₄ at a given T

JEE Main 2020 (Online) 7th January Evening Slot

MCQ (Single Correct Answer)

-1

The equation that is incorrect is :

$${\left( {\Lambda _m^0} \right)_{KCl}} - {\left( {\Lambda _m^0} \right)_{NaCl}} = {\left( {\Lambda _m^0} \right)_{KBr}} - {\left( {\Lambda _m^0} \right)_{NaBr}}$$

$${\left( {\Lambda _m^0} \right)_{NaBr}} - {\left( {\Lambda _m^0} \right)_{NaI}} = {\left( {\Lambda _m^0} \right)_{KBr}} - {\left( {\Lambda _m^0} \right)_{NaBr}}$$

$${\left( {\Lambda _m^0} \right)_{NaBr}} - {\left( {\Lambda _m^0} \right)_{NaCl}} = {\left( {\Lambda _m^0} \right)_{KBr}} - {\left( {\Lambda _m^0} \right)_{KCl}}$$

$${\left( {\Lambda _m^0} \right)_{{H_2}O}} = {\left( {\Lambda _m^0} \right)_{HCl}} + {\left( {\Lambda _m^0} \right)_{NaOH}} - {\left( {\Lambda _m^0} \right)_{NaCl}}$$

JEE Main 2020 (Online) 7th January Morning Slot

MCQ (Single Correct Answer)

-1

Given that the standard potentials (E^o) of Cu²⁺/Cu and Cu⁺/Cu are 0.34 V and 0.522 V respectively, the E^o of Cu²⁺/Cu⁺ :

- 0.182 V

- 0.158 V

0.182 V

+0.158 V

JEE Main 2019 (Online) 12th April Morning Slot

MCQ (Single Correct Answer)

-1

Given

CO³⁺ + e^– $$ \to $$ CO₂⁺ ; E^o = + 1.81 V

Pb⁴⁺ + 2e^– $$ \to $$ Pb₂⁺ ; E^o = + 1.67 V

Ce⁴⁺ + e^– $$ \to $$ Ce³⁺ ; E^o = + 1.61 V

Bi³⁺ + 3e^– $$ \to $$ Bi ; E^o = + 0.20 V

Oxidizing power of the species will increase in the order :

Co³⁺ < Ce⁴⁺ < Bi³⁺ < Pb⁴⁺

Co³⁺ < Pb⁴⁺ < Ce⁴⁺ < Bi³⁺

Ce⁴⁺ < Pb⁴⁺ < Bi³⁺ < Co³⁺

Bi³⁺ < Ce⁴⁺ < Pb⁴⁺ < Co³⁺

PREVIOUS NEXT

JEE Main Subjects