JEE Main 2025 (Online) 4th April Morning Shift | Electrochemistry Question 4 | Chemistry

JEE Main 2025 (Online) 4th April Morning Shift

MCQ (Single Correct Answer)

-1

On charging the lead storage battery, the oxidation state of lead changes from $x_1$ to $y_1$ at the anode and from $x_2$ to $y_2$ at the cathode. The values of $x_1, y_1, x_2, y_2$ are respectively :

$0,+2,+4,+2$

$+2,0,0,+4$

$+4,+2,0,+2$

$+2,0,+2,+4$

JEE Main 2025 (Online) 3rd April Evening Shift

MCQ (Single Correct Answer)

-1

The standard cell potential $\left(\mathrm{E}_{\text {cell }}^{\ominus}\right)$ of a fuel cell based on the oxidation of methanol in air that has been used to power television relay station is measured as 1.21 V . The standard half cell reduction potential for $\mathrm{O}_2\left(\mathrm{E}_{\mathrm{O}_2 / \mathrm{H}_2 \mathrm{O}}^{\circ}\right)$ is 1.229 V .

Choose the correct statement:

Reactants are fed at one go to each electrode.

Oxygen is formed at the anode.

The standard half cell reduction potential for the reduction of $\mathrm{CO}_2\left(\mathrm{E}_{\mathrm{CO}_2 / \mathrm{CH}_3 \mathrm{OH}}^{\circ}\right)$ is 19 mV

Reduction of methanol takes place at the cathode.

JEE Main 2025 (Online) 3rd April Morning Shift

MCQ (Single Correct Answer)

-1

Correct order of limiting molar conductivity for cations in water at 298 K is :

$\mathrm{H}^{+}>\mathrm{Na}^{+}>\mathrm{K}^{+}>\mathrm{Ca}^{2+}>\mathrm{Mg}^{2+}$

$\mathrm{H}^{+}>\mathrm{Ca}^{2+}>\mathrm{Mg}^{2+}>\mathrm{K}^{+}>\mathrm{Na}^{+}$

$\mathrm{Mg}^{2+}>\mathrm{H}^{+}>\mathrm{Ca}^{2+}>\mathrm{K}^{+}>\mathrm{Na}^{+}$

$\mathrm{H}^{+}>\mathrm{Na}^{+}>\mathrm{Ca}^{2+}>\mathrm{Mg}^{2+}>\mathrm{K}^{+}$

JEE Main 2025 (Online) 29th January Evening Shift

MCQ (Single Correct Answer)

-1

Match List - I with List - II :

List - I (Applications)	List - II (Batteries/Cell)
(A) Transistors	(I) Anode - Zn/Hg; Cathode - HgO + C
(B) Hearing aids	(II) Hydrogen fuel cell
(C) Inverters	(III) Anode - Zn; Cathode - Carbon
(D) Apollo space ship	(IV) Anode - Pb; Cathode - Pb \| PbO₂

Choose the correct answer from the options given below :

(A)-(III), (B)-(I), (C)-(IV), (D)-(II)

(A)-(II), (B)-(III), (C)-(IV), (D)-(I)

(A)-(IV), (B)-(III), (C)-(II), (D)-(I)

(A)-(III), (B)-(II), (C)-(IV), (D)-(I)

PREVIOUS NEXT

JEE Main Subjects