AIEEE 2003 | Electrochemistry Question 177 | Chemistry

For a cell reaction involving a two-electron change, the standard e.m.f. of the cell is found to be 0.295 V at 25^oC. The equilibrium constant of the reaction at 25^oC will be

29.5 $$\times$$ 10^-2

1 $$\times$$ 10¹⁰

1 $$\times$$ 10^-10

AIEEE 2002

MCQ (Single Correct Answer)

-1

Conductivity (Seimen’s S) is directly proportional to area of the vessel and the concentration of the solution in it and is inversely proportional to the length of the vessel then, then constant of proportionality is expressed in :

Sm mol^-1

Sm² mol^-1

S^-2m² mol

S²m² mol^-2

AIEEE 2002

MCQ (Single Correct Answer)

-1

For the following cell with hydrogen electrodes at two different pressure p₁ and p₂. What will be the emf for the given cell :

$$\eqalign{ & Pt({H_2})|{H^ + }(aq)|Pt({H_2}) \cr & \,\,\,\,\,{p_1}\,\,\,\,\,\,\,\,\,\,\,\,\,\,1M\,\,\,\,\,\,\,\,\,\,\,\,{p_2} \cr} $$

$${{RT} \over F}{\log _e}{{{P_1}} \over {{P_2}}}$$

$${{RT} \over 2F}{\log _e}{{{P_1}} \over {{P_2}}}$$

$${{RT} \over F}{\log _e}{{{P_2}} \over {{P_1}}}$$

none of these

AIEEE 2002

MCQ (Single Correct Answer)

-1

EMF of a cell in terms of reduction potential of its left and right electrodes is :

E = E_left - E_right

E = E_left + E_right

E = E_right - E_left

E = -(E_right + E_left)