1
JEE Main 2020 (Online) 7th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
The equation that is incorrect is :
A
$${\left( {\Lambda _m^0} \right)_{KCl}} - {\left( {\Lambda _m^0} \right)_{NaCl}} = {\left( {\Lambda _m^0} \right)_{KBr}} - {\left( {\Lambda _m^0} \right)_{NaBr}}$$
B
$${\left( {\Lambda _m^0} \right)_{NaBr}} - {\left( {\Lambda _m^0} \right)_{NaI}} = {\left( {\Lambda _m^0} \right)_{KBr}} - {\left( {\Lambda _m^0} \right)_{NaBr}}$$
C
$${\left( {\Lambda _m^0} \right)_{NaBr}} - {\left( {\Lambda _m^0} \right)_{NaCl}} = {\left( {\Lambda _m^0} \right)_{KBr}} - {\left( {\Lambda _m^0} \right)_{KCl}}$$
D
$${\left( {\Lambda _m^0} \right)_{{H_2}O}} = {\left( {\Lambda _m^0} \right)_{HCl}} + {\left( {\Lambda _m^0} \right)_{NaOH}} - {\left( {\Lambda _m^0} \right)_{NaCl}}$$
2
JEE Main 2020 (Online) 7th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Given that the standard potentials (Eo) of Cu2+/Cu and Cu+/Cu are 0.34 V and 0.522 V respectively, the Eo of Cu2+/Cu+
A
- 0.182 V
B
- 0.158 V
C
0.182 V
D
+0.158 V
3
JEE Main 2019 (Online) 12th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
The decreasing order of electrical conductivity of the following aqueous solutions is :
0.1 M Formic acid (A),
0.1 M Acetic acid (B),
0.1 M Benzoic acid (C)
A
A > B > C
B
C > B > A
C
A > C > B
D
C > A > B
4
JEE Main 2019 (Online) 12th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Given
CO3+ + e $$ \to $$ CO2+ ; Eo = + 1.81 V
Pb4+ + 2e $$ \to $$ Pb2+ ; Eo = + 1.67 V
Ce4+ + e $$ \to $$ Ce3+ ; Eo = + 1.61 V
Bi3+ + 3e $$ \to $$ Bi ; Eo = + 0.20 V
Oxidizing power of the species will increase in the order:
A
Co3+ < Ce4+ < Bi3+ < Pb4+
B
Co3+ < Pb4+ < Ce4+ < Bi3+
C
Ce4+ < Pb4+ < Bi3+ < Co3+
D
Bi3+ < Ce4+ < Pb4+ < Co3+
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