1
JEE Main 2019 (Online) 12th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Given

CO3+ + e $$\to$$ CO2+ ; Eo = + 1.81 V

Pb4+ + 2e $$\to$$ Pb2+ ; Eo = + 1.67 V

Ce4+ + e $$\to$$ Ce3+ ; Eo = + 1.61 V

Bi3+ + 3e $$\to$$ Bi ; Eo = + 0.20 V

Oxidizing power of the species will increase in the order :
A
Co3+ < Ce4+ < Bi3+ < Pb4+
B
Co3+ < Pb4+ < Ce4+ < Bi3+
C
Ce4+ < Pb4+ < Bi3+ < Co3+
D
Bi3+ < Ce4+ < Pb4+ < Co3+
2
JEE Main 2019 (Online) 10th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Which one of the following graphs between molar conductivity ($${\Lambda _m}$$) versus $$\sqrt C$$ is correct ?
A
B
C
D
3
JEE Main 2019 (Online) 10th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Consider the statements S1 and S2

S1 : Conductivity always increases with decrease in the concentration of electrolyte.

S2 : Molar conductivity always increases with decrease in the concentration of electrolyte.

The correct option among the following is :
A
Both S1 and S2 are wrong
B
S1 is correct and S2 is wrong
C
Both S1 and S2 are correct
D
S1 is wrong and S2 is correct
4
JEE Main 2019 (Online) 9th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
A solution of Ni(NO3)2 is electrolysed between platinum electrodes using 0.1 Faraday electricity. How many mole of Ni will be deposited at the cathode?
A
0.10
B
0.15
C
0.20
D
0.05
EXAM MAP
Medical
NEET
Graduate Aptitude Test in Engineering
GATE CSEGATE ECEGATE EEGATE MEGATE CEGATE PIGATE IN
CBSE
Class 12