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1
JEE Main 2019 (Online) 12th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Given
CO3+ + e– $$ \to $$ CO2+ ; Eo = + 1.81 V
Pb4+ + 2e– $$ \to $$ Pb2+ ; Eo = + 1.67 V
Ce4+ + e– $$ \to $$ Ce3+ ; Eo = + 1.61 V
Bi3+ + 3e– $$ \to $$ Bi ; Eo = + 0.20 V
Oxidizing power of the species will increase in the order:
A
Co3+ < Ce4+ < Bi3+ < Pb4+
B
Co3+ < Pb4+ < Ce4+ < Bi3+
C
Ce4+ < Pb4+ < Bi3+ < Co3+
D
Bi3+ < Ce4+ < Pb4+ < Co3+
2
JEE Main 2019 (Online) 9th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
A solution of Ni(NO3)2 is electrolysed between platinum electrodes using 0.1 Faraday electricity. How many mole of Ni will be deposited at the cathode?
A
0.10
B
0.15
C
0.20
D
0.05
3
JEE Main 2019 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
The standard Gibbs energy for the given cell reaction in kJ mol–1 at 298 K is :
Zn(s) + Cu2+ (aq) $$ \to $$ Zn2+ (aq) + Cu (s),
E° = 2 V at 298 K
(Faraday's constant, F = 96000 C mol–1)
A
384
B
–192
C
–384
D
192
4
JEE Main 2019 (Online) 8th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Calculate the standard cell potential in (V) of the cell in which following reaction takes place : Fe2+(aq) + Ag+(aq) $$ \to $$ Fe3+(aq) + Ag (s)

Given that
$$E_{A{g^ + }/Ag}^o = xV$$
$$E_{Fe^{2+ }/Fe}^o = yV$$
$$E_{Fe^{3+ }/Fe}^o = zV$$
A
x + 2y - 3z
B
x - z
C
x - y
D
x + y - z
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