JEE Main 2019 (Online) 8th April Morning Slot | Electrostatics Question 111 | Physics

JEE Main 2019 (Online) 8th April Morning Slot

MCQ (Single Correct Answer)

-1

The bob of a simple pendulum has mass 2g and a charge of 5.0 μC. It is at rest in a uniform horizontal electric field of intensity 2000 V/m. At equilibrium, the angle that the pendulum makes with the vertical is : (take g = 10 m/s²)

tan^–1(5.0)

tan^–1(2.0)

tan^–1(0.5)

tan^–1(0.2)

JEE Main 2019 (Online) 8th April Morning Slot

MCQ (Single Correct Answer)

-1

A solid conducting sphere, having a charge Q, is surrounded by an uncharged conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge of –4 Q, the new potential difference between the same two surfaces is :

–2V

JEE Main 2019 (Online) 12th January Morning Slot

MCQ (Single Correct Answer)

-1

Determine the electric dipole moment of the system of the three charges, placed on the vertices of an equilateral triangle, as shown in the figure :

JEE Main 2019 (Online) 12th January Morning Slot Physics - Electrostatics Question 113 English

JEE Main 2019 (Online) 12th January Morning Slot Physics - Electrostatics Question 113 English

$$2q\ell \widehat j$$

$$\left( {q\ell } \right){{\widehat i + \widehat j} \over {\sqrt 2 }}$$

$$\sqrt 3 \,q\ell {{\widehat j - \widehat i} \over {\sqrt 2 }}$$

$$ - \sqrt 3 \,q\ell \widehat j$$

JEE Main 2019 (Online) 11th January Morning Slot

MCQ (Single Correct Answer)

-1

Three charges Q, + q and + q are placed at the vertices of a right-angle isosceles triangle as shown below. The net electrostatic energy of the configuration is zero, if the value of Q is :

JEE Main 2019 (Online) 11th January Morning Slot Physics - Electrostatics Question 114 English