JEE Main 2025 (Online) 8th April Evening Shift | Heat and Thermodynamics Question 39 | Physics

Water falls from a height of 200 m into a pool. Calculate the rise in temperature of the water assuming no heat dissipation from the water in the pool.

(Take g = 10 m/s², specific heat of water = 4200 J/(kg K))

0.36 K

0.23 K

0.48 K

0.14 K

JEE Main 2025 (Online) 7th April Evening Shift

MCQ (Single Correct Answer)

-1

The helium and argon are put in the flask at the same room temperature (300 K). The ratio of average kinetic energies (per molecule) of helium and argon is:

(Give: Molar mass of helium = 4 g/mol, Molar mass of argon = 40 g/mol)

1 : $ \sqrt{10} $

10 : 1

1 : 10

1 : 1

JEE Main 2025 (Online) 7th April Evening Shift

MCQ (Single Correct Answer)

-1

Match List - I with List - II.

List - I	List - II
(A) Isothermal	(I) ΔW (work done) = 0
(B) Adiabatic	(II) ΔQ (supplied heat) = 0
(C) Isobaric	(III) ΔU (change in internal energy) ≠ 0
(D) Isochoric	(IV) ΔU = 0

Choose the correct answer from the options given below :

(A)-(III), (B)-(II), (C)-(I), (D)-(IV)

(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

(A)-(IV), (B)-(II), (C)-(III), (D)-(I)

(A)-(IV), (B)-(I), (C)-(III), (D)-(II)

JEE Main 2025 (Online) 7th April Morning Shift

MCQ (Single Correct Answer)

-1

Match the List I with List II

	List - I		List - II
(A)	Triatomic rigid gas	(I)	$\frac{C_p}{C_v}=\frac{5}{3}$
(B)	Diatomic non-rigid gas	(II)	$\frac{C_p}{C_v}=\frac{7}{5}$
(C)	Monoatomic gas	(III)	$\frac{C_p}{C_v}=\frac{4}{3}$
(D)	Diatomic rigid gas	(IV)	$\frac{C_p}{C_v}=\frac{9}{7}$