JEE Main 2022 (Online) 25th June Evening Shift | Heat and Thermodynamics Question 146 | Physics

A solid metallic cube having total surface area 24 m² is uniformly heated. If its temperature is increased by 10$$^\circ$$C, calculate the increase in volume of the cube. (Given $$\alpha$$ = 5.0 $$\times$$ 10^$$-$$4 $$^\circ$$C^$$-$$1).

2.4 $$\times$$ 10⁶ cm³

1.2 $$\times$$ 10⁵ cm³

6.0 $$\times$$ 10⁴ cm³

4.8 $$\times$$ 10⁵ cm³

JEE Main 2022 (Online) 25th June Evening Shift

MCQ (Single Correct Answer)

-1

A copper block of mass 5.0 kg is heated to a temperature of 500$$^\circ$$C and is placed on a large ice block. What is the maximum amount of ice that can melt? [Specific heat of copper : 0.39 J g^$$-$$1 $$^\circ$$C^$$-$$1 and latent heat of fusion of water : 335 J g^$$-$$1]

1.5 kg

5.8 kg

2.9 kg

3.8 kg

JEE Main 2022 (Online) 25th June Evening Shift

MCQ (Single Correct Answer)

-1

The ratio of specific heats $$\left( {{{{C_P}} \over {{C_V}}}} \right)$$ in terms of degree of freedom (f) is given by :

$$\left( {1 + {f \over 3}} \right)$$

$$\left( {1 + {2 \over f}} \right)$$

$$\left( {1 + {f \over 2}} \right)$$

$$\left( {1 + {1 \over f}} \right)$$

JEE Main 2022 (Online) 25th June Morning Shift

MCQ (Single Correct Answer)

-1

The relation between root mean square speed (v_rms) and most probable sped (v_p) for the molar mass M of oxygen gas molecule at the temperature of 300 K will be :

$${v_{rms}} = \sqrt {{2 \over 3}} {v_p}$$

$${v_{rms}} = \sqrt {{3 \over 2}} {v_p}$$

$${v_{rms}} = {v_p}$$

$${v_{rms}} = \sqrt {{1 \over 3}} {v_p}$$

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